(a) 3 cos (3x + 2) = 2 over the interval (-π, π]. (b) 2 sin(2x - 3) = 4 over the interval (0, 2. π]. (c) 2 cos(2x - 3) = 0 over the interval (-, 3. π]. Pay attention to the interval. (d) tan(2x - 3) = 2 over the interval (-3, 3-π].

Q: -p² sin(w) cos?(w) – p cos² (») -p2 sin(4).

A:

Q: 1//2 x8 Evaluate: sin" (1-2x')+ cos" (2axvi-x")} dx. 2x²)+cos* 1-x4 -1/V2

A:

Q: Find the value →21. csc (sec- 2) + cos (tan¬1 (– V3))

A:

Q: θ = cos^-1[sin(LT1) sin(LT2) + cos(LT1) cos(LT2) cos(LN1 − LN2)] How does this formula go with…

A: Consider the figure as our Earth. O is the center of the earth Point P on the earth surface has…

Q: If z = 2 ( cos 2¥/3 + isin 2¥/3 ), then z^3=   i. 2 - i8√3 ii. -4 + i4√3 iii.-8-i√2 iv. -8 - i4

A: Using de-moivre's formula :

Q: (b) S tan3 x sec² x dx c) S sin³x cos5 x dx

A: The explanation of the solution is :

Q: 4 sec(8) = find cot(0) 2

A: Use trigonometric rations

Q: 2. Explain why arcsin(sin(0)) = 0 but arcsin(sin(807)) # 807

A: Concept  arcsin(sin x) = x   is true  only when x lie in the interval [-π/2 , π/2]

Q: Find the exact value of the expression whenever it is defined.

A: (a) sin-1-22 -π2≤x≤π2 sin x=-22 multiply and divide by 12 sin x =12  sin x = π4 sin-1-22=π4

Q: Prove the following trigonometric identities. 1 cotx a) 6 cosx| 6 cosx = 6sin² x COSX CSCX

A: The details solution is given below

Q: 2 cos "(\) tan-

A:

Q: First, recall that sin²2 (0) = 1 - cos² (0). Thus, substitute (1 - cos²(0)) for sin²(0) in the given…

A: Now we know that sin^2(theta)=1-cos^2(theta)

Q: 6) y=-sin (3x) - 1

A: 6. The given function y=-sin3πx-1. We have to sketch the graph of the function and find its domain…

Q: sin( 2 tan-1 (x/ 12)) = Select one:

A: Can solve the given function by using double angle formula

Q: sin* x – cos* x = 1 x – cos? x

A:

Q: 8.) k(x)=-2 tan(2(x+)) Period = Increment =

A: Given function is: kx=-2tan2x+π8 Then the period of this function is 2π2=π. The increment is π8.

Q: (arctan o tan)' = 1 – pi k E z°(k +1/2)pi When differentiating on the Real line is this true?

A:

Q: Wouldn't tan(x+pi)-(-sin(x)) yield tan(x+pi) + sin(x)) instead of tan(x+pi) - sin(x))?

A: Yes , there is a mistake on that question. I give u correct solution .  tan(x + π) - cos( x + (π/2))…

Q: (cos A + sin A)/(cos A - sin A) = (1+ sin(2A))/ cos(2A)

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)