A = -3 4 0 -2 30 -8 8 1 B = = [10 1 -1 0 0 1 0 0 b= || 1 0 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Is A similar to B? If yes, find an invertible matrix such that P^-1AP = В.
Find A^10 b by writing b as linear combination of eigenvectors of А.

A
=
-3 4
0
-2 3 0
-8
8 1
-
9
B =
1
OTO
0
0
0 −1
-1 0
1
0
1
9
b
=
0
3
Transcribed Image Text:A = -3 4 0 -2 3 0 -8 8 1 - 9 B = 1 OTO 0 0 0 −1 -1 0 1 0 1 9 b = 0 3
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