College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A 27.0-kg box is released on a 27 ∘ incline and accelerates down the incline at 0.30 m/s^2 .

 

Find the friction force impeding its motion.
Express your answer to two significant figures and include the appropriate units.
Expert Solution
Check Mark
Step 1

component of gravitational force down the incline 

= mgSin27° = 27×9.8×Sin27° = 120.12 N 

friction force act up the incline 

Now, by Newton's 2nd law 

120.12 - f = 27×0.3 

f = 112.02 N

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