A 240-V 50-Hz, 4-pole, universal motor operates at a speed of 10000 rpm on full load. The series field winding impedance is 0.65 + j1.4 № and the armature circuit impedance is 1.35 +j1.6 Q. If the back emf of the motor is 150 -25⁰ V and the rotational loss is 30 W, calculate: (a) the output power, (b) the output torque, and (c) the efficiency of the motor.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter32: Three-phase Motors
Section: Chapter Questions
Problem 6RQ: Name three factors that determine the torque produced by an induction motor.
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NOTE: back emf is 150
A 240-V 50-Hz, 4-pole, universal motor operates at a speed of 10000 rpm
on full load. The series field winding impedance is 0.65 + j1.4 Q and the
armature circuit impedance is 1.35 +j1.6 Q. If the back emf of the motor
is 150 -25⁰ V and the rotational loss is 30 W, calculate: (a) the output
power, (b) the output torque, and (c) the efficiency of the motor.
Transcribed Image Text:A 240-V 50-Hz, 4-pole, universal motor operates at a speed of 10000 rpm on full load. The series field winding impedance is 0.65 + j1.4 Q and the armature circuit impedance is 1.35 +j1.6 Q. If the back emf of the motor is 150 -25⁰ V and the rotational loss is 30 W, calculate: (a) the output power, (b) the output torque, and (c) the efficiency of the motor.
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