A 2012 study of freely forming groups in bars all over Europe examined the naturalbehavior of groups. The researchers recorded the group size (number of individuals in thegroup) of all 501 groups in the study that were naturally laughing. The findings weredisplayed in the figure below.Number of groups30025020015010050025421683522145Laughter group size66Carefully examine the information provided, then answer the following questions.1. What is the median laughter group size? 22. The average laughter group size is [Select]3. The distribution of laughter group size categorical

The question is about graphical representation and measuresGiven :From bar graph :To find :1 )…

Answered: A 2012 study of freely forming groups…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
In an interview for a job, the interviewer says that the average annual income of the company's 16 employees is $73,610. The actual annual incomes of the 16 employees are shown below. Which measure of central tendency would be most informative to the potential employee? OOO O O median O mode O mean Orange $12,500 $12,500 $16,430 $17,305 $17,408 $18,980 $20,432 $24,540 $25,676 $28,906 $28,956 $32,654 $94,024 $98,213 $250,921 $478,320
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
The following table shows some data from a study on substance use among 10th graders in the United States and Europe. Smoked Cigarettes Cigarette-Free Totals U.S. 14,000 Europe 96,000 Total 71,210 110,000
Which of the following data sets shows categorical data? Course Grade 72 78 85 90 98 Class Size 22 23 25 28 32 Flight Number 1002 1274 4012 5661 7812 Number of Coins 1 3 4 8 19
Chapter 13 A researcher wants to determine whether there is a difference in the mean age of community college prófessors, publiC university professors, and private university professors. Professors from each were randomly selected across America and their ages were recorded. The data is given below. Test whether there is a difference in the mean ages. Find the P-Value. Community College Public University Private University 23 38 45 28 36 45 27 41 39 37 47 61 52 42 36 25 31 35 O 0.3571 O 0.2357 O 0.1142 O 0.2289
Moving to another question will save this response. Question 5 Obtain the five-number summary for the given data. The test scores of 15 students are listed below. 42 45 50 53 57 61 67 68 75 76 85 87 90 94 95 O 42, 53, 71.5, 87, 95 42, 52.25, 71.5, 85.5, 95 O 42, 53, 68, 87, 95 O 42, 52.25, 68, 85.5, 95 A Moving to another question will save this response. earch F2 DII F3 F4 F5 PrtS 5 W
In a recent study, a scientist was interested in investigating whether there is a significant difference in the number of sleeping hours in different moon phases: waxing crescent, full moon, and waning crescent. Participants’ number hour of sleep were recorded in the table below. Quality of sleeps (in number of hours) Waxing Crescent Full Moon Waning Crescent 7 8 9 7 8 4 5 4 3 6 5 7 8 9 6 What are the groups being compared? That is, what are the levels of the IV? What is the IV? What is the level of measurement of the IV?
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Hospitals In a study of births in New York State, data were collected from four hospitals coded as follows: (1) Albany Medical Center; (1438) Bellevue Hospital Center; (66) Olean General Hospital; (413) Strong Memorial Hospital. Does it make sense to calculate the average (mean) of the numbers 1, 1438, 66, and 413?

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