A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from the ceiling at an angle of 50.00 to the vertical. When the pendulum ball is released from the rest position. it swings to the very bottom of the motion where it collides head-on with a 1. 40-kg block that is initially at rest on a level surface. If the pendulum ball recolls at 1.50 m/s. what is the speed of the block after the collision? 6= 50° 1.2 m 2.0 kg 1,4 kg a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.76 m's e. 3.03 m/s

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**Pendulum and Collision Problem**

A 2.0-kg pendulum ball is attached to a light, uniform cable of length 1.20 m, which hangs from the ceiling at an angle of 50.0° to the vertical. When the pendulum ball is released from this rest position, it swings to the lowest point of its motion. There, it collides head-on with a 1.4-kg block that is initially at rest on a level surface. If the pendulum ball's recoil speed is 1.50 m/s, what is the speed of the block after the collision?

**Diagram Explanation:**

- The diagram shows a pendulum system. 
- The pendulum consists of a 2.0-kg spherical ball attached to a string of length 1.2 m.
- The cable forms an angle of 50° with the vertical when the pendulum is positioned at rest.
- The pendulum swings downward and collides with a stationary 1.4-kg block on the level ground.

**Possible Options for the Speed of the Block:**

a. 5.98 m/s  
b. 3.88 m/s  
c. 6.29 m/s  
d. 4.75 m/s  
e. 3.03 m/s  

The task is to determine the speed of the block after the collision using principles of conservation of momentum and energy, considering the given conditions of the pendulum's release and collision.
Transcribed Image Text:**Pendulum and Collision Problem** A 2.0-kg pendulum ball is attached to a light, uniform cable of length 1.20 m, which hangs from the ceiling at an angle of 50.0° to the vertical. When the pendulum ball is released from this rest position, it swings to the lowest point of its motion. There, it collides head-on with a 1.4-kg block that is initially at rest on a level surface. If the pendulum ball's recoil speed is 1.50 m/s, what is the speed of the block after the collision? **Diagram Explanation:** - The diagram shows a pendulum system. - The pendulum consists of a 2.0-kg spherical ball attached to a string of length 1.2 m. - The cable forms an angle of 50° with the vertical when the pendulum is positioned at rest. - The pendulum swings downward and collides with a stationary 1.4-kg block on the level ground. **Possible Options for the Speed of the Block:** a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.75 m/s e. 3.03 m/s The task is to determine the speed of the block after the collision using principles of conservation of momentum and energy, considering the given conditions of the pendulum's release and collision.
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