A 2.00 kg object is subjected to three forces that give it an acceleration a = -(8.00m/2)i + (6.00 m/,2). If two of the three forces are F (30.0N)i+ (16.0N)j and F = -(12.0N)i + (8.00N)f, find the third force in Newtons.
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- Check Your Understanding Find the angle between forces F1and F3in Example 2.16.= 7. Four forces act on an object, given by A = 40.0 Neast, B = 50.0 north, C 70.0 N west, and D = 90.0 N south. (a) What is the magnitude of the net force on the object? (b) What is the direc- tion of the force?Two forces act on a 4.15-kg object: 31.1 N in the +x direction and 68.5 N in the -y direction. What is the amount of the object's acceleration (in m/s )? [3 sig. figs.] Answer. -9.01 What is the direction of the object's acceleration (in degrees counterclockwise from +x) [3 sig. figs.] Answer. 75.2
- Two dogs are pulling on a weird-shaped twig of a tree in different directions. The first dog pulls with force F; = (10.0î – 20. 4j)N , the second dog pulls with force F2 = (-15.0î – 6. 5j)N . What is the angle between forces F, and F2?At what angle 9 must the 410-lb force be applied in order that the resultant R of the two forces have a magnitude of 950 lb? For this condition what will be the angle 3 between R and the horizontal? 410 lb 720 lb Answers: 0= i 38 B = i ♡ 0A force F = (9.501 - 3.50t ĵ) N, with t in units of s, is applied to a 2.00 kg object initially at rest. (a) At what time (in s) will the object be moving with a speed of 15.0 m/s? (Round your answer to at least two decimal places.) 2.963 X 7 dv Find the acceleration vector of the object using Newton's second law, and note that a = Integrate a with respect to time to find as a function of time. Note that at t = 0 the object is at rest, so the constants of integration are zero. Set the magnitude of the dt velocity vector equal to the speed, and solve the resulting equation for t. s (b) How far (in m) is the object from its initial position when its speed is 15.0 m/s? 22.221 X In order to find the object's position at the given time, you need to integrate the velocity equation. Assume the object starts at the origin, so the constants of integration are zero. Find the magnitude of your resulting position vector, and the time calculated from part (a), to find the distance. m (c) What is…
- ( 45 a M > 1:0Y HW1.pdf > Chapter 1 HW1 Exercises 1. A force P = 800 N is shown in Fig. a. Find the y-component of P with respect to x and y axis. b. Find the y'-component of P with respect to x' and y' axis. c. Find the y-component of P with respect to x' and y axis. d. Find the y'-component of P with respect to x and y' axis. P = 800 N X' 2. A block is resting on an incline of slope 5:12 as shown in Fig. It is subjected to a force F = 500 N on a slope of 3:4. Determine the components of F parallel and perpendicular to the incline. F = 500 NThere are two forces on the 2.00 kg box in the overhead view of but only one is shown. For F1 = 20.0N,a =12.0 m/s^2and θ= 30.0 degree find the second force (a) in unit-vector notation and as (b) a magnitude and (c) an angle relative to the positive direction of the x axis.Three people are pulling a heavy object along the floor with forces A, B and C as shown in the figure. What is the resultant (i.e. suml of the three forces? The forces are given by (all angles are CCW from + x-axis): A = magnitude 20 N, direction 30º. B = magnitude 40 N, direction 140°. C= magnitude 30 N, direction 240º. в А х-ахis
- OA balanced net force must be applied. OAn unbalanced net force must be applied. O The net force must be zero. O The net force must be greater than the applied force. Question 3(Multiple Choice Worth (01.03 LC) For an object at rest, the normal force equals the gravitational force. What is the sum of these forces called? O Net force OUnbalanced force O Inertia O Potential force Question 4Multiple Choice (01.03 LC) What kind of motion will an object have when forces on it are balanced? OIt will not move at all. Previous Question Question 1 (Answered) 吕口 F3 F1 O00 DOD F4 F2You place a Box wing to 265.4 N on an inclined plane that makes a 43.5゚ angle with the horizontal. compute the component of the gravitational force acting down the inclined plane. answer in units of N.At what angle must the 330-lb force be applied in order that the resultant R of the two forces have a magnitude of 1000 lb? For this condition what will be the angle ß between R and the horizontal? 330 lb 770 lb Answers: 0 = 8 B = i 0