A 2-in.-square aluminum strut is maintained in the position shown by a pin support at A and by sets of rollers at B and C that prevent rotation of the strut in the plane of the figure. Knowing that LAB = 4 ft, determine (a) the largest values of LBC and LCD that can be used if the allowable load P is to be as large as possible,

A 2-in.-square aluminum strut is maintained in the position shown by a pin support at A and by sets of rollers at B and C that prevent rotation of the strut in the plane of the figure. Knowing that LAB = 4 ft, determine (a) the largest values of LBC and LCD that can be used if the allowable load P is to be as large as possible,

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.5.2P

See similar textbooks

Similar questions

*4-76 The C83400-red-brass rod AB and 2014-T6-alu- minum rod BC are joined at the collar B and fixed connected at their ends. If there is no load in the members when T₁ = 50°F, determine the average normal stress in each member when T₂ = 120°F. Also, how far will the collar be displaced? The cross-sectional area of each member is 1.75 in². 3 ft B 2 ft C
Each bar of the truss has a rectangular cross section, 30 mm by 60 mm. Determine the maximum vertical load P that can be applied at B if the working stresses are 100 MPa in tension and 80 MPa in compression. (A reduced stress in compression is specified to reduce the danger of buckling.) B 8m Gm 10m
A flexural member is fabricated from two flange plates 1/2x16 and a web plate 1/4x20, thusforming a built-up ‘I’ shape member. The yield stress of the steel is 50 ksi.a. Compute the plastic section modulus Z and the plastic moment Mp with respect to the majoraxis.b. Compute the section modulus S and the plastic moment My with respect to the major axis
x Determin the design Compressive 12-5 Strength of the Cross- sectiona Column shown with unbraced length kala= 35m, Kyly=2m A-118:75 I= 10872 Iy= 3799 J-247 8a e =4.13 c ? J= 247-8 %3D Tu = 9.57 C 5.746 E=2-1x
W3D 25 Y= 155 %31 1oow= 2500 KN 27=310mm X= 475 Z= 60 %3D 102=600mm
Name: Time you spent to solve the problem HW- 3 ID.: 'Dėtërminë thé forċés in all the members, and state if these memibers are in tension or compression. Use table to arrange your Cal&tlations, show the results on the truss ( if not your witf täke zerở)** 30 N 4m 3 т 15
The assembly consists of two red brass C83400 copper rods AB and CD having a diameter of 30 mm, a 304 stainless steel rod EF having a diameter of 40 mm, and a rigid member G. If the supports at A, C, and F each have a stiffness of k= 200 MN/m determine the average normal stress developed in the rods when the load is applied. A C -300 mm- 30 mm 30 mm B D G E 450 mm 40 kN 40 kN 40 mm F
The horizontal bar ABC is supported by a pin at A and two rods with identical cross- sectional areas. The rod at B is steel and the rod at C is aluminum. Neglecting the weight of the bar, determine the force in each rod when the force P = 80 kN is applied. Use Est = 200 GPa and Eal = 70 GPa. %3D Steel Aluminum A B T2 m- 1.5 m- Im
Homework: A helica) cast steel with 3. helix angle has to tanmiz 35 KW at 1500 YPu. Gear has 24 teeth, 2 full depth. Tha Static Stress for Cast Steel maybe taken as 56 Mpa.. The width. of face may be talcen as 8 time) th module. Assum e : Cs =l, Ep=E= Ges=300 HPa , be =60 MPa, Calculate: WA, WNm, b, VR, = 200G Pa C=40.
Check the slenderness of the steel section against Local Buckling. 340 mm Use Fy = 800 MPa. O Compact Slender I O Adequate 400 mm None of the choices 30 mm 20 mm 20 mm
A column is built up from four (4)- 125 x 125 x 18 angle shapes as shown. The plates are not continuous but are spaced at intervals along the column length and function to maintain the separation of the angles. They do not contribute to the cross-sectional properties. The effective length is 4 m. Compute the allowable design compressive strength based on flexural buckling. E= 250 MPa. Use ASD. k 375 mm 125mm, HPlate 125mm 4 - 4 125 × 125× l8 section 下好业

Н WWWN 160kN 140kN 120kN 100kN 130kN 150kN 8 panels @ 6m ea. = 48m 10.8m 8.1m D Determine the force in the members and identify each if (T) - tension or (C) - compression. HI= DG= DE= IJ = 419.444kN T HJ= НК - KJ = JM = 425kN T KL - EG GF EF FI = 419.444kN T FH = GH = || = 9.6m 10.5m