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A 1x working solution contains 50mM of EDTA. What is the EDTA concentration in your 91x concentrated stock solution? Round your result to 2 decimal points.
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- A water sample was analyzed for Fe content using the iron- phenanthroline method. The following data were obtained from the analysis: Reagent Blank Absorbance Absorbance (au) Reagent Blank Absorbance 0.003 Concentration of Stock Solution: 10 ppm Volume of Stock Solution (mL) Total Volume of Standard Solution Concentration of Standard Solution (ppm) Absorbance (au) (mL) 0.50 10.00 0.012 1.00 10.00 0.132 2.00 10.00 0.267 3.00 10.00 0.349 4.00 10.00 0.428 5.00 10.00 0.560 Volume of Unknown Solution Total Volume of Unknown Solution Trial Absorbance (au) (mL) (mL) 1 5.00 10.00 0.289 2 5.00 10.00 0.296 3 5.00 10.00 0.281 Determine the value of the slope (m), y-intercept (b), and the coefficient of determination (r²) A m = 0.1128; b = -4.0 x 10-5; r2 = 0.9880 B m = 0.1128; b = -4.0 x 10-5; r² = 0.9762 C) m = 0.1128; b = -3.0 x 10-³; r² = 0.9880 D m = 0.1128; b = -3.0 x 10-³; r² = 0.9762Table 2: Absorbance Values of Standards and Unknowns. Sample Blank Standard Solution 1 Standard Solution 2 Standard Solution 3 Standard Solution 4 Standard Solution 5 Water Sample 1 Water Sample 2 Phosphate Concentration (in ppm) Y17 0 ppm 0.02 ppm 0.04 ppm 0.08 ppm 0.16 ppm 0.32 ppm Freeman Lake 0.001 0.325 0.292 0.413 0.315 0.039 0.054 0.049 Absorbance at 2= 690 nm Calculations: 1. Construct a phosphate standard curve in Excel by plotting concentration (in ppm) on your x-axis and Absorbance (unitless) on your y-axis for your known solutions. Label the axes on the graph and provide the curve with a title. Use a linear trendline to generate a best fit line to your data. Label the graph with the equation and the R" value. Insert your labeled graph in the space below. XCalcium in a 50-uL serum sample is titrated with 1.85 x 10-4 M EDTA solution, requiring 2.5 mL. What is the calcium concentration in the blood? (EDTA and Ca react with each other in 1:1 ratio) (molar mass of Ca is 40)
- From the data in Table 2.5, compute the concentration of the undiluted and diluted ovalbumin samples (make sure to account for the appropriate dilution factors, DF, in the computation).A water sample was analyzed for iron content using the iron-phenanthroline method. Using the set of data from Question 15 (as presented below), Reagent Blank Absorbance Absorbance (au) Reagent Blank Absorbance 0.003 Concentration of Stock Solution: 10 ppm Volume of Stock Solution (mL) Total Volume of Standard Solution (mL) 0.50 10.00 1.00 10.00 2.00 10.00 3.00 10.00 4.00 10.00 5.00 10.00 Volume of Trial Unknown Solution (mL) 1 5.00 2 5.00 3 5.00 find the true concentration of Fe2+ of the original sample. A) 5.12 ppm B) 2.56 ppm 2.52 ppm D) 5.05 ppm Concentration of Standard Solution (ppm) Total Volume of Unknown Solution (mL) 10.00 10.00 10.00 Absorbance (au) 0.012 0.132 0.267 0.349 0.428 0.560 Absorbance (au) 0.289 0.296 0.281Standardization of EDTA was done using MgSO4 standard wherein a 50-mL aliquot of solution obtained from 0.480 g MgSO4 in 500 mL needed 39.4 mL of the EDTA solution to reach the endpoint. Determine how many milligrams of CaCO3 will react per mL of this EDTA solution.
- 0.49850 g of CaCO3 (100.0869 g/mol) is dissolved in HCl solution and diluted to 500 mL. A 25 mL aliquot is titrated with 23.62 mL EDTA solution. 100 mL tap water is titrated with 30.13 mL of the same EDTA solution. What is the total hardness of the tap water (as ppm CaCO3)?A phamacist reconstituted a vial of 750 mg Cefuroxime Sodium Powder for Injection with 6mL of sterile water for injection. The reconstituted solution was dark amber-colored solution. The package insert states that solution colors range from clear to yellow depending on concentration, diluent, and storage conditions. The pharmacist was then hesitant to give the patient the solution due to its unusual dark color. Five portions were taken from a batch of cefuroxime sodium. Prior to testing in the instrument, each part was subjected to one of the following conditions: Conditions Specifications Temperature Portion 1: 8°C ± 2°C Portion 2: 30°C ± 2°C Portion 3: 40°C ± 2°C Light Portion 4: Kept in the dark Portion 5: Exposed to direct sunlight a. Which form of the product – the powder for injection, the reconstituted product, or both – will you subject to the following conditions and why? b. Will you also expose the reference standard of cefuroxime sodium to the same…20.0 mL water sample was titrated with 0.0100 M EDTA solution that required 14.50 mL for CaCO3 hardness. The total hardness of the water sample in terms of CaCO3 (MW = 100.1 g/mole) in parts per million is _________? Note: Express final answer using least number of significant figures. 2. If 35.2 mL of EDTA solution is required to reach the endpoint with 0.3120-g of primary standard grade CaCO3 (MW = 100.1 g/mole), the normal concentration of the EDTA (MW = 292.24) solution is _________ N?
- I PUIRE UVVIS spectrophotometry of water sample containing cobalt (Co) and nickel (Ni) is performed in a lab. In the beginning, blank reading is taken by taking in the cuvette. A Water only Both A and C Water sample having Ni and Co Co and Ni solutionYou took 25.00 mL of unknown water solution and titrated it with EDTA. The EDTA solution molarity was 0.01 M, and it took 16.50 mL to reach the end point. With the blank it took only 0.98 mL to reach end point. A) How many milliliters of EDTA solution were used to titrate hardness that actually came from the unknown? B) How many moles of EDTA reacted with hardness-causing ions from the unknown sample? C) How many moles of hardness-causing ions were present in the unknown sample? D) Assuming that the total hardness of water is due to CaCO3, how many grams CaCO3 does it correspond to? E) What is the total hardness of the unknown water in ppm CaCO3?Calcium in a 255-µL serum sample is titrated with 0.0002379 M EDTA solution, requiring 5.6 mL. What is the calcium (40.078 g/mol) concentration in the blood sample in mg/dL?