A 1-L unbuffered solution needs the pH adjusted from 6 to 1. How many mL of 12 molar HCl solution need to be added to reduce the pH?

100.0 mL of HCI required 25.00 mL of 0.2000 M Mg(OH)2 to reach pH 7. What is the concentration of the HCI ? 2 HCI + Mg(OH)₂ MgCl₂ + 2 H₂O The neutralization equation is There is enough information to calculate the moles of Mg(OH)2 ( L Mg(OH)₂ (- concentration = Then use stoichiometry to convert moles of Mg(OH)₂ into moles of HCI mol HCI a. acid i. 0.2000 p. 0.01000 mol Mg(OH)₂ (- b. base c. HCI d. NaOH mol Mg(OH)2 We now can calculate the concentration of HCI since we have both the moles of HCI and the volume of HCI j. 1.000 k. 0.005000 q. 0.001000 1 L mol HCI LHCI r. 58.31 = mol Mg(OH)2 e. NaCl I. 100.0 f. H₂O m. 0.1000 s. 5.831 = g. 25.00 mol/L n. 0.05000 h. 0.02500 mol Mg(OH)2 o. 2.000 mol HCI

Explain the difference between pH value of distilled water and the theoretical pH expected.

Determine the molar concentrations of Ca2+ and CI- in a 0.38 M calcium chloride solution. 1) 0.38 M Ca2+ and 0.38 M CI- O 2) 00.19 M Ca2+ and 0.38 M CI- 3) 0.38 M Ca2+ and 0.76 M CI- 4) 0.19 M Ca2+ and 0.76 M CI- O 5) None of the above