
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:**Precipitation Reaction Problem**
**Question:**
A 185.0 mL sample of 1.200 M Pb(NO₃)₂ is mixed with 123.50 mL of 1.500 M NaCl, and the PbCl₂ precipitate is filtered from the solution. Then 200.0 mL of 3.000 M NaBr is added to the remaining solution, and the PbBr₂ precipitate is also collected and dried. What is the mass (in grams) of the PbBr₂ precipitate, assuming the yield in each precipitation step is 100%?
**Analysis:**
1. **Reaction 1: Formation of PbCl₂**
- Solutions mixed: 185.0 mL of 1.200 M Pb(NO₃)₂ and 123.50 mL of 1.500 M NaCl.
- Precipitate formed: PbCl₂.
2. **Reaction 2: Formation of PbBr₂**
- Remaining solution: After filtration of PbCl₂.
- Added solution: 200.0 mL of 3.000 M NaBr.
- Precipitate formed: PbBr₂.
**Objective:**
Calculate the mass of the PbBr₂ precipitate.
**Key Assumptions:**
- 100% yield for each precipitation step.
**Calculation Steps:**
- Determine moles of each reactant.
- Identify the limiting reactant for each reaction.
- Calculate moles of PbBr₂ formed.
- Convert moles of PbBr₂ to grams using its molar mass.
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