A 170-pF capacitor and a 680-pF capacitor are both charged to 1.70 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate. (a) Find the resulting potential difference across each capacitor. V₁ kV kV 170 pF V₂ 680 pF = (b) Find the energy lost when the connections are made. µJ
A 170-pF capacitor and a 680-pF capacitor are both charged to 1.70 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate. (a) Find the resulting potential difference across each capacitor. V₁ kV kV 170 pF V₂ 680 pF = (b) Find the energy lost when the connections are made. µJ
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Introduction:
When we apply voltage across conductor, it accumulates charge.
This charge is directly proportional to voltage. It is given as
Here is the capacitance.
We first find the charge on each capacitor and then total charge. We then find voltage across each capacitor when joined. We also find the loss of energy.
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