A 100 W light bulb designed to operate at 120 V has a filament with a resistance of 144 Ω.  What constraints are on the design of the filament?  Why cannot just any 144 Ω resistance be used as a filament for the bulb?

(a) Given a 52.0 V battery and 20.0 Ω and 84.0 Ω resistors, find the current (in A) and power (in W) for each when connected in series. I20.0 Ω= A P20.0 Ω= W   I84.0 Ω= A P84.0 Ω= W (b)Repeat when the resistances are in parallel. I20.0 Ω= A P20.0 Ω= W  I84.0 Ω= A P84.0 Ω= W

You have an aluminum bar of dimensions 2.0 cm × 5.0 cm × 10 cm. You want to insert it into an electric circuit so that it will have the smallest possible resistance.   Which pair of opposite faces should you connect to the circuit?

None of the resistors in the circuit shown in the drawing is connected in series or in parallel with one another. Find (a) the current Is and the resistances (b) R2 and (c) R3. R = 4.0 2 9.0 A 75.0 V R2 12.0 A R3 6.0 A R4 - 2.0 2 I5 R5 = 2.2 a (a) Number i Units (b) Number i Units (c) Number i Units eTextbook and Media > > >

A 39.4-Ω resistor and a 19.5- resistor are connected in series across a 12.7-V battery. What is the voltage across (a) the 39.4- resistor and (b) the 19.5- resistor?

(a) Three 5.30 Ω resistors are connected in series to a 20.0 V battery. What is the equivalent resistance (in Ω) of the circuit?   What is the current (in A) in each resistor?   (b) Three other 5.30 Ω resistors are all connected in parallel across a second 20.0 V battery. What is the equivalent resistance (in Ω) of this circuit?   What is the current (in A) in each resistor in this circuit?

(a)Calculate the equivalent resistance (in Ω) between points a and b.  Ω (b)If a voltage of 41.0 V is applied between points a and b, find the current (in A) in each resistor. 12 Ω  A 6.0 Ω A 5.0 Ω A 4.0 Ω A 8.0 Ω