A 100 g glass container contains 250 g of water at 15.0 °C. A 70 g piece of unknown material at 100 °C is added to the water in the container. The final temperature of the mixture is 19.0 °C. What is the specific heat of the unknown material in J/kg "C? (specific heat of water = 4,186 J/kg "C, specific heat of glass=837.2 J/kg "C)

How much kilojoule (kJ) of heat is required to increase the temperature of a liquid from 13.2°C to 32.2°C when the mass of the liquid is 0.88 kg? The specific heat of the liquid is 2.47 kJ/(kg °C)

2.6 of water at 28 °C is added to 5.0 of water at 69 ° C. What is the temperature of the mixture in °C if no energy was lost? ( specific heat of water is 4186 J/Kg ^ C)

A refrigerator door is opened and room-temperature air (20°C) fills the 1.50 m 3 compartment. A 10.0 kgm turkey, also at room temperature, is placed in the refrigerator and the door is closed. The density of air is 1.20 kgm/m3 and its specific heat is 1020 J / kgm °C. Assume the specific heat of a turkey, like that of a human, is 3480 J / kgm °C. How much heat must the refrigerator remove from its compartment to bring the air and the turkey to thermal equilibrium at a temperature of 5°C? Assume no heat exchange with the surrounding environment.

A thermally isolated container has 479 grams of water in it and a 376 gram plastic block. The water had an initial temperature of 352 K. The plastic had an initial temperature of 300 K. The plastic and water reach an equilibrium temperature of 342 K. Water has a specific heat of 4.182 J/(gram K). What is the specific heat of the plastic block in J/(gram K)?

A plastic cup of negligible mass contains 0.280 kg of an unknown liquid at a temperature of 30.0 °C. A 0.0270 kgkg mass of ice at a temperature of 0.0°C°C is added to the liquid, and when thermal equilibrium is reached the temperature of the combined substances is 14.0 °C°C. Assuming no heat is exchanged with the surroundings, what is the specific heat capacity of the unknown liquid? Express your answer in joules per kilogram-kelvin.

An ice chest at a beach party contains 12 cans of soda at 4.41 °C. Each can of soda has a mass of 0.35 kg and a specific heat capacity of 3800 J/(kg C°). Someone adds a 9.77-kg watermelon at 23.4 °C to the chest. The specific heat capacity of watermelon is nearly the same as that of water. Ignore the specific heat capacity of the chest and determine the final temperature T of the soda and watermelon in degrees Celsius.

When the indoor temperature of a house is 25°C and the outdoor temperature is -8°C, the inside and outside surfaces of the glass are measured to be 21.4°C and 18.1°C.  If the glass has an area of 3.06 m2 and a thickness of 6.23 mm, what is the rate of heat (in W) lost though the window [round your final answer to zero decimal places]? {kglass = 0.78 W/m∙K}

We have 39.5 g of a particular substance. Its specific heat in solid form is 0.8 J/(g K) and its specific heat in liquid form is 1.4 J/(g K); it's latent heat of melting is 170 J/g. Its initial temperature is 196 and its melting point is 223. We wish to raise its temperature to 297 (where it is a liquid). How much heat is required?

Heat is added to 1 kg of water such that the temperature increases by 5 K. The specific heat capacity of water is 4, 180 J/(kg.K). The specific heat capacity of iron is 450 J/(kg.K). If the same amount of heat is added to 5 kg of iron, how much will the temperature increase? O 7.28 K O 12.28 K O 10.28 K O 9.28 K