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A 10 cm long solenoid with 860 turns and radius R = 3.0 cm has a 200 mA current flowing through it. B Honlo √1+(2R/L)2 |Π| ΑΣΦ Submit xa a b B= 1.983 10 √x √√x <-4 x x Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining 1X1 Review | Constants | Periodic X ? X.10n Tesla

A 10 cm long solenoid with 860 turns and radius R = 3.0 cm has a 200 mA current flowing through it. B Honlo √1+(2R/L)2 |Π| ΑΣΦ Submit xa a b B= 1.983 10 √x √√x <-4 x x Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining 1X1 Review | Constants | Periodic X ? X.10n Tesla

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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By reversing the direction of the current flowing through the solenoid, one can swap north and south poles of the solenoid. Inside the ideal solenoid (one which is infinitely long with very tight coils), the magnetic field lines are parallel to the axis and are equally spaced. In other words, the magnetic field is uniform. It has the same magnitude everywhere within the solenoid. The magnetic field inside an exceptionally long solenoid is proportional to the current and to the number of turns per unit length of the solenoid: B = μ¸nI₂ = μ₂ where: 14. = a constant = 1.2566×10= 1.2566×10 N 1₂7²₁ n == L N n = the number of turns per unit length of the solenoid = /₁ where: N is the total number of turns, I is the length of the solenoid I, = the current running in the solenoid B=- ܐܬܐܨܬܬ = 1.2566×10 The slope me of the magnetic field B vs. current I for infinitely long solenoid (coil) is equal to √1+(28/1)² B vs. I slope me = Hon = Ho = For real solenoids, which are not infinitely long, but have the length L and the radius R. the Eq. (2) changes into A 1 (2R (2) (3)
Transcribed Image Text:By reversing the direction of the current flowing through the solenoid, one can swap north and south poles of the solenoid. Inside the ideal solenoid (one which is infinitely long with very tight coils), the magnetic field lines are parallel to the axis and are equally spaced. In other words, the magnetic field is uniform. It has the same magnitude everywhere within the solenoid. The magnetic field inside an exceptionally long solenoid is proportional to the current and to the number of turns per unit length of the solenoid: B = μ¸nI₂ = μ₂ where: 14. = a constant = 1.2566×10= 1.2566×10 N 1₂7²₁ n == L N n = the number of turns per unit length of the solenoid = /₁ where: N is the total number of turns, I is the length of the solenoid I, = the current running in the solenoid B=- ܐܬܐܨܬܬ = 1.2566×10 The slope me of the magnetic field B vs. current I for infinitely long solenoid (coil) is equal to √1+(28/1)² B vs. I slope me = Hon = Ho = For real solenoids, which are not infinitely long, but have the length L and the radius R. the Eq. (2) changes into A 1 (2R (2) (3)
A 10 cm long solenoid with 860 turns and radius R = 3.0 cm has a 200 mA current flowing through it. B= Honlo √1+(2R/L)² ΠΙ ΑΣΦ x" Xb √x vx b B= 1.983 10-4 X x Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining IXI Review | Constants | Periodic ? X.10n 2 Tesla
Transcribed Image Text:A 10 cm long solenoid with 860 turns and radius R = 3.0 cm has a 200 mA current flowing through it. B= Honlo √1+(2R/L)² ΠΙ ΑΣΦ x" Xb √x vx b B= 1.983 10-4 X x Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining IXI Review | Constants | Periodic ? X.10n 2 Tesla
Expert Solution
Step 1

Given value---

  • length = 10 cm.
  • number of turns = 860 .
  • radius = 3 cm.
  • current = 200 mA.

We have to find---

  • Magnetic field inside the solenoid ?
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