A 10 cm long rectangular bar (when subjected to a tensile load) deforms by 0.1 mm. Calculate the normal strain.
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A 10 cm long rectangular bar (when subjected to a tensile load) deforms by 0.1 mm. Calculate the normal strain.
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- A homogenous steel rod has a diameter of 1.5 inches. When a load is applied, it deformed to about 0.045 inches. If the length of the rod is 6 ft and the modulus of elasticity is E=29x10^6 psi. Determine the force applied in kilopounds (kips).2. Given that a steel cylinder of dimenslons 12.0 mm in dlameter and 70 mm long is subjected to tensicn. (a) Determine the modulus of elasticity in the figure below. (b) Using the figure below, calculate the deformation in the steel cylinder subjected to 15 kN tension for ce. 600 500 400 500 400E 300 300 200 200 100 100 0.000 0.002 0.004 0.006 Strain 8.00 0.04 0.03 0.12 0.16 0.20 Strain Tensile stress-strain behavior for a steel alloy. Daccri be io v our MP MOrds the throo ctrongthanin g arnin cize rad uction colid Stress (MPa) Stress (MPa)Determine the modulus of Elasticity E for a material that has proportional stress of 100 MPa and proportional strain of 0.001. Select one: a. 1 GPa b. 100 GPa C. 0.1 MPa d. 1000 kPa
- During laboratory testing of an 8-inch aluminum-alloy rod with a cross sectional area of 0.32in, a tensile load of 40,000 lbs.is applied. If the cross sectional area decreases to 0.3188in and lengthens to 8.021 inches, what is the Modulus of Elasticity and Poisson's Ratio? 29. E= 6/8 v =-ɛ(lateral)/E(axial)A cylindrical bar of steel 9.9 mm (0.3898 in.) in diameter is to be deformed elastically by application of a force along the bar axis. Determine the force that will produce an elastic reduction of 3.0×10-3 mm (1.181 ×10-4 in.) in the diameter. For steel, values for the elastic modulus (E) and Poisson's ratio (v) are, respectively, 207 GPa and 0.30. i NA cylindrical bar of aluminum 1.75 in diameter is to be deformed elastically by application of a force along the bar axis. Determine the force that produces an elastic reduction of 5.0x10-3 mm in the diameter.
- A bar of diameter 30 mm is subjected to a tensile Load such that the measured extension on a gauge length of 200 mm is 0.09 mm and the change in diameter is 0.0045 mm. Calculate the Poisson Ratio:The data shown in the following table are from a tensile test of high-strength steel. TENSILE-TEST DATA Load (lb) Elongation (in.) 1,000 0.0002 2,000 0.0006 6,000 0.0019 10,000 0.0033 12,000 0.0039 12,900 0.0043 13,400 0.0047 13,600 0.0054 13,800 0.0063 14,000 0.0090 14,400 0.0102 15,200 0.0130 16,800 0.0230 18,400 0.0336 20,000 0.0507 22,400 0.1108 22,600 Fracture The test specimen has a diameter of 0.505 in. and a gage length of 2.00 in. (see figure). Gage length P At fracture, the elongation between the gage marks is 0.12 in. and the minimum diameter is 0.42 in. Plot the conventional stress-strain curve for the steel. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet. Determine the proportional limit, modulus of elasticity (the slope of the initial part of the stress-strain curve), yield stress at 0.1% offset, ultimate stress, percent elongation in 2.00 in. (at fracture), and percent reduction in area (at fracture). (Enter…A 20-ft wrought iron bar that is ½ inch in diameter is subjected to a tensile force of 3 kips. Determine the a) stress in psi, b) elongation of the bar in inches, and c) strain. The modulus of elasticity of wrought iron E = 29 x 103 ksi.
- 7. A 3000 kgf tensile load is applied on a steel bar of 3.25 cm diameter. When the same load is applied to an aluminum bar, it is found to give the same elastic strain. Esteel = 2.1x10° kgf/cm? and Eal = 0.7 x10° kgf/cm?. Calculate the diameter of aluminum bar.1 - An aluminum plate is subjected to uniform stress along its boundaries, as shown in the figure. Determine the change of length of diagonal BD. 120mm 120 MPa 160mm C B V 100MPa -200 MPa E-80GPa ✓=0.3 G=30MPaA steel rod has a length of 4 ft, and a diameter of 3 inches. Determine the amount of stress in the rod due to a tension force of 5,000 lb. What is the longitudinal strain in the dod? The modulus of elasticity is E= 30 x 106 psi.