A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is nitially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction? velocity:

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
100%
Please solve and answer the question correctly. Thank you!!
**Question:**

A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction?

**Solution:**

To find the velocity after impact, use the principle of conservation of momentum. 

**Momentum before impact:**
- Falcon: \( m_1 \cdot v_1 = 1.75 \, \text{kg} \times 28.5 \, \text{m/s} \)
- Dove: \( m_2 \cdot v_2 = 0.255 \, \text{kg} \times 5.95 \, \text{m/s} \)

**Total momentum before impact:**
\[ 
(m_1 \cdot v_1) + (m_2 \cdot v_2) 
\]

**Momentum after impact:**
- Combined mass after collision: \( m_1 + m_2 = (1.75 + 0.255) \, \text{kg} \)

The velocity \( v \) after impact is:
\[ 
v = \frac{(m_1 \cdot v_1) + (m_2 \cdot v_2)}{m_1 + m_2} 
\]

Fill in the answer in the space provided:

**Velocity:** ______ m/s
Transcribed Image Text:**Question:** A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction? **Solution:** To find the velocity after impact, use the principle of conservation of momentum. **Momentum before impact:** - Falcon: \( m_1 \cdot v_1 = 1.75 \, \text{kg} \times 28.5 \, \text{m/s} \) - Dove: \( m_2 \cdot v_2 = 0.255 \, \text{kg} \times 5.95 \, \text{m/s} \) **Total momentum before impact:** \[ (m_1 \cdot v_1) + (m_2 \cdot v_2) \] **Momentum after impact:** - Combined mass after collision: \( m_1 + m_2 = (1.75 + 0.255) \, \text{kg} \) The velocity \( v \) after impact is: \[ v = \frac{(m_1 \cdot v_1) + (m_2 \cdot v_2)}{m_1 + m_2} \] Fill in the answer in the space provided: **Velocity:** ______ m/s
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Momentum
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON