A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is nitially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction? velocity:

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**Question:**

A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction?

**Solution:**

To find the velocity after impact, use the principle of conservation of momentum. 

**Momentum before impact:**
- Falcon: \( m_1 \cdot v_1 = 1.75 \, \text{kg} \times 28.5 \, \text{m/s} \)
- Dove: \( m_2 \cdot v_2 = 0.255 \, \text{kg} \times 5.95 \, \text{m/s} \)

**Total momentum before impact:**
\[ 
(m_1 \cdot v_1) + (m_2 \cdot v_2) 
\]

**Momentum after impact:**
- Combined mass after collision: \( m_1 + m_2 = (1.75 + 0.255) \, \text{kg} \)

The velocity \( v \) after impact is:
\[ 
v = \frac{(m_1 \cdot v_1) + (m_2 \cdot v_2)}{m_1 + m_2} 
\]

Fill in the answer in the space provided:

**Velocity:** ______ m/s
Transcribed Image Text:**Question:** A 1.75 kg falcon catches a 0.255 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 28.5 m/s and the dove's velocity is 5.95 m/s in the same direction? **Solution:** To find the velocity after impact, use the principle of conservation of momentum. **Momentum before impact:** - Falcon: \( m_1 \cdot v_1 = 1.75 \, \text{kg} \times 28.5 \, \text{m/s} \) - Dove: \( m_2 \cdot v_2 = 0.255 \, \text{kg} \times 5.95 \, \text{m/s} \) **Total momentum before impact:** \[ (m_1 \cdot v_1) + (m_2 \cdot v_2) \] **Momentum after impact:** - Combined mass after collision: \( m_1 + m_2 = (1.75 + 0.255) \, \text{kg} \) The velocity \( v \) after impact is: \[ v = \frac{(m_1 \cdot v_1) + (m_2 \cdot v_2)}{m_1 + m_2} \] Fill in the answer in the space provided: **Velocity:** ______ m/s
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