College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Question 20 A 0.0052kg bullet moving at 672m/s strikes a 0.7kg wooden block at rest on a frictionless surface. As the bullet emerges, its speed is reduced to 428m/s as it travels in the same direction. What is the speed of the bullet-block center of mass? (Answer in 2 decimal places, no unit) UNIT: m/sarrow_forwardA small block of mass M is released from rest at the top of the curved frictionless ramp shown in the figure. The block slides down the ramp and is moving with a speed of 3.50 m/s when it collides with a larger block mass 1.5M at rest at the bottom of the incline. The larger block moves to the right with a speed of 2m/s immediately after the collision. Express your answer in speed of the small block after the collision in terms of the given quantities and fundamental constants. •.. 1.5M 3.50 (m/s) M –1.50(m/s)M A V small block M 2 М — 1.50 V small block M 3.50(m/s) M- 3(m/s)M (c) v small block M ЗМ — 1.50М V small block Marrow_forwardA 83.2 g marble moving at 10.2 m/s approaches and collides head-on with a stationary 41.8 g marble. Assuming that the collision is elastic, what are the corresponding kinetic energy of each marble?arrow_forward
- In the figure below, a 3.1 kg box of running shoes slides on a horizontal frictionless table and collides with a 1.8 kg box of ballet slippers initially at rest on the edge of the table, at height = 0.40 m. The speed of the 3.1 kg box is 5.0 m/s just h before the collision. If the two boxes stick together because of packing tape on their sides, what is their kinetic energy just before they strike the floor? ។ harrow_forwardA small block of mass M is released from rest at the top of the curved frictionless ramp shown in the figure. The block slides down the ramp and is moving with a speed of 3.50 m/s when it collides with a larger block mass 1.5M at rest at the bottom of the incline. The larger block moves to the right with a speed of 2m/s immediately after the collision. Express your answer in speed of the small block after the collision in terms of the given quantities and fundamental constants. ... 1.5M 2 M - 1.50 A V small block M ЗМ— 1.50M в) V small block M 3.50 (m/s) M-3(m/s)M © v V small block M 3.50 (m/s) M- 1.50(m/s) M D V small block Marrow_forwardThe figure below shows a bullet of mass 15 g traveling horizontally towards the east with speed 250 m/s, which strikes a block of mass 1.5 kg that is initially at rest on a frictionless table. After striking the block, the bullet is embedded in the block and the block and the bullet move together as one unit. What is the energy loss in the system due to this collisionarrow_forward
- Two balls of mass m and M are attached by strings of length L. The two balls are initially at rest at an angle θ, and are then released. The balls undergo a totally inelastic collision at the bottom of their swings. Assume that m = 1.7kg, M = 2.8kg, L = 0.80m and θ = 67o.a) Calculate the speed of the balls immediately after the totally inelastic collision.b) To what maximum angle do the conjoined balls rise after the collision?arrow_forwardA 100-kg particle moves with an initial velocity of (4.0i, - 6.0j) m/s. If its velocity changes to v = (3.0i – 8.0j) m/s by the action of a force, determine The net work done on the particle. What principle would you use to solve this problem? The impulse on the particle. True or False: Impulse is equal to the rate of change of momentum.arrow_forwardA 7.17 g pellet is shot horizontally from a BB gun at a speed of 24.8 m/s into a 28.7 g wooden block. The wooden block is attached to a spring and lies on a frictionless table. If the collision is inelastic and the spring constant k = 16.0 N/m, what is the maximum compression of the spring?arrow_forward
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