A 1.580 g of vitamin C ( a monoprotic acid, ie reacts one to one vs NaOH like Vinegar) was dissolved in water and required 32.58 m L of 0.1580 M solution of sodium hydroxide to titrate. What was the % by weight of Vitamin C in the sample? (Molar mass of Vitamin C is 176.0 g/mol)

Use the data below to determine the % by mass of Fe to TWO decimal places, if a 0.019 M KMnO4 solution was used for the titration. (MM Fe = 56 g/mol) mass of iron compound (g) 0.637 initial buret reading (mL) 0.86 16.60 final buret reading (mL) Type your answer...

6. A 0.4622-g sample of potassium hyd rogen phthalate was dissolved in 50 mL of deionized water and titrated to a phenolphthalein end-point with 19.48 mL of NaOH solution. What is the molarity of the NaOH? 7. Assuming that the density of vinegar is 1.012 g/m L, calculate the weight percent of acetic acid in vinegar if 23.85 mL of 0.1311 M NaOH was required to titrate 5.00 mL of vinegar. did HA nd dis 192 riw o asuuc no'noleauoetb s obulbo. As 900 900 4Coz2 anigll .asbtucf namheqx dini 209 (0 HoO Cag) (es) ibis 9C D DV 9 ballet tnabole A 9 u u 1oied qütenud orlf hi asiddud e 9t borsoog szib alddud sis ord nolt dsvawnlcrndtuodA 9l il blucwnolduloe HOe wans uoy nistqx3 Sipid oo! tstse : wot oo dhelom t bbs rg beau yilednobbos nsbile s est itbin ow osta isrl bsbne evicmi Srtulce HOs orts to yahelom orld ininetsb as 9 adant anoto toi n odslo 613 Exbiont Aorf

Calculate the mass of the solid product in grams that the student can recover