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A 1.500 g sample of iron ore, labeled A, was processed accordingly to give 0.5215 g of pure Fe2O3 (159.69 g/mol). A second sample of iron ore, labeled B, weighed 1.750 g and gave 0.5097 g of pure Fe2O3.

A 1.500 g sample of iron ore, labeled A, was processed accordingly to give 0.5215 g of pure Fe2O3 (159.69 g/mol). A second sample of iron ore, labeled B, weighed 1.750 g and gave 0.5097 g of pure Fe2O3.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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28. A 1.500 g sample of iron ore, labeled A, was processed accordingly to give 0.5215 g of pure Fe2O3 (159.69 g/mol). A second sample of iron ore, labeled B, weighed 1.750 g and gave 0.5097 g of pure Fe2O3. 

If you were the CEO of the mining company that dug up these ores, which should you sell at a higher price and why? A) Ore A, because of a lower mass of the sample B Ore B, because of a higher mass of the sample c) Ore A, because of a higher %Fe D Ore B, because of a higher %Fe
Transcribed Image Text:If you were the CEO of the mining company that dug up these ores, which should you sell at a higher price and why? A) Ore A, because of a lower mass of the sample B Ore B, because of a higher mass of the sample c) Ore A, because of a higher %Fe D Ore B, because of a higher %Fe
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