A 1.0 cm tall light bulb is placed 50 cm from a convex lens that has a focal distance of 40 cm. Which of the following statements is true of the bulb's image? a. The image is virtual, the distance to the image is 12.5 cm and the height of the image is 0.25 cm tall. b. The image is virtual, the image distance is -200 cm and the height of the image is 4.0 cm tall. c. The image is real, the distance to the image is 22.2 cm and the height of the image is 0.44 cm tall. d. The image is real, the distance to the image is 200 cm and the height of the image is 4.0 cm tall. e. The image is virtual, the distance to the image is 22.2 cm and the height of the image is 0.44 cm tall.

A candle located 36 cm away from a thin convex lens that has a focal length of 9 cm. What type of image is formed?

An object is placed 4cm left of a converging lens with a focal length of 10cm. a. Make a sketch of this arrangement and draw 3 principal rays to find where the image should form.   b. Is the image real or virtual? c. Use the thin lens equation to calculate the position of the image. d. (New situation) An object is placed 30 cm to the left of a diverging lens of focal length 20 cm. Sketch this arrangement by drawing 3 principal rays. Draw where you think the image should form

A spherical mirror creates a picture. The object's magnification is -2.0.. Virtual or real? Is it upright or flipped? Does the mirror have a convex or convex shape In which direction should I look to find the reflection in the mirror?

3. An object sits 23 cm in front of a diverging mirror. An image is formed 14 cm behind the mirror. What is the focal length of the mirror? a. b. What is the magnification of the image?

To view an insect, an entomologist places a converging lens with a focal length of 10 cm a distance of 8.0 cm from the insect. What will be the magnification of the insect's image? O a. +4 b. +3 O c. +6 d. +7 O e. +5

A 2-cm-tall object is 30 cm from a converging lens of focal length 12 cm, as shown in the figure. a. Use ray tracing to locate the image of the object. Use a ruler to do this accurately. Make your best estimate of the image distance by making measurements on your diagram. b. Is the image real or virtual? Is the image upright or inverted? c. Now calculate the exact location and height of the image. fj = 12 cm 2 cm 30 сm

A converging lens with a focal length of 12 cm forms a real image of 7.40 mm tall and 18.000 cm to the right of the lens. (a) Determine the position and size of the object. ст mm Is the image upright or inverted? A. Upright B. Inverted Are the object and image on the same size or opposite sides of the lens? You should draw the ray-diagram for this situation. A. same B. oppsite

132. An object is placed at a distance of 80 cm left of a converging lens with a focal length of 30 cm. Calculate the image distance. Is the image virtual or real? If the object is 8 cm tall, what is the size of the image? A diverging lens with the same focal length is placed 10 cm right of the first lens. Determine final image position and magnification.

A lens forms an image of an object. The object is 15.4 cm from the lens. The image is 11.7 cm from the lens on the same side as the object. a. What is the absolute value of the focal lens of the lens? cm b. Is the lens converging or diverging? converging diverging c. If the object is 8.48 mm tall, how tall is the image? mm d. Is the image upright or inverted? upright O inverted e. To receive full credit for this problem you will need to draw a principal ray diagram, including three principal rays. yes, got it - I will attach the diagram in Canvas with the rest of my work. no, I don't have a diagram to attach.