A 1 20 50 60 30 centimeters 10 40 70 B 10 20 30 centimeters 40 50 60 70 C 30 10 20 40 50 60 70 centimeters millimeters millimeters millimeters

A hook A is at (1 m, -2 m, 2 m). A force ?⃑ = {−6?̂+ 9?̂+ 3? } ? is exerted on the hook. Deterine the angle between the force and the position vector ?⃑??, where O is the origin of thecoordinate system. Show the diagram.

A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30° with the horizontal. Part a (#599119) (Inclined Plane) What is the weight of the block?

A narrow uniform rod has length 2a. The linear mass density of the rod is p. so the mass m of a length of the rod is pl. Part A A point mass is located a perpendicular distance from the center of the rod. Calculate the magnitude of the force that the rod exerts on the point mass. (Hint: Let the rod be along the y-axis with the center of the rod at the origin, and divide the rod into infinitesimal segments that have length dy and that are located at coordinate y. The mass of the segment is dm = pdy. Write expressions for the I- and y-components of the force on the point mass, and integrate from a toa to find the components of the total force). Express your answer in terms of the gravitational constant G and some or all of the variables m, p, a, and r. IVE ΑΣΦ ? a xa Xb √x xx x b IXI F= Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining The correct answer does not depend on: la Part B n(n+1)2 + n(n−1)(n−2) 1+nz+ T³ +... (|1| < 1).) What does your result…

The object shown in (Figure 1) is in equilibrium. Suppose |FO| = 10 N. Figure Fo 2.0 m Massless F₁ 1.0 m < F₂ 1 of 1 Part A What is the magnitude of F₁? Express your answer with the appropriate units. Submit |F₁| Value N You have already submitted this answer. Enter a new answer. No credit lost. Try again. Part B CHμA |F₂| = What is the magnitude of F2? Express your answer with the appropriate units. Submit Previous Answers Request Answer Provide Feedback μA Value Request Answer ? Units ?

E To Two blocks, labeled D and E, are connected by an essentially massless string that runs over an essentially massless and frictionless pulley, as shown in Figure 2, above. Block E hangs straight down and is initially moving downward with a speed of 3.82 meters per second. Block D is on an inclined plane, inclined at an angle of theta = 0 = 28.6 degrees above horizontal. There is no friction between block D and most of the plane, but there is friction (with a coefficient of kinetic friction equal to 0.49) between block D and a region of length L = 0.628 meters. Block D will slide over that region (and pass it completely) before it gets to the end of the plane. Block D has a mass of 0.74 kg, while block E has a mass of 0.98 kg. The only significant forces acting on the blocks are friction acting on block D (while in contact with the region with friction), normal forces, tension forces, and gravity (with g = 9.81 m/s2). Calculate the speed of block D (in units of meters per second)…