A 0.6883 gram sample of impure potassium chlorate was treated with 45.00 mL of 0.1020 M Fe(NH4)2(SO4)2. The reaction is: ClO3-+6Fe2++6H+->Cl-+6Fe3++3H2O When the reaction was complete, the excess Fe(II) was back-titrated with 9.004 mL of 0.01734 M K2Cr2O7. Cr2O7-+6Fe2++14H+->2Cr3++6Fe3++7H2O Calculate the percent KClO3 (FW = 122.55) in the sample.
A 0.6883 gram sample of impure potassium chlorate was treated with 45.00 mL of 0.1020 M Fe(NH4)2(SO4)2. The reaction is: ClO3-+6Fe2++6H+->Cl-+6Fe3++3H2O When the reaction was complete, the excess Fe(II) was back-titrated with 9.004 mL of 0.01734 M K2Cr2O7. Cr2O7-+6Fe2++14H+->2Cr3++6Fe3++7H2O Calculate the percent KClO3 (FW = 122.55) in the sample.
Chemistry by OpenStax (2015-05-04)
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Chapter19: Transition Metals And Coordination Chemistry
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Problem 11E: Iron (II) can be oxidized to iron (III) by dichromate ion, which is reduced to chromium (III) in...
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A 0.6883 gram sample of impure potassium chlorate was treated with 45.00 mL of 0.1020 M Fe(NH4)2(SO4)2. The reaction is:
ClO3-+6Fe2++6H+->Cl-+6Fe3++3H2O
When the reaction was complete, the excess Fe(II) was back-titrated with 9.004 mL of 0.01734 M K2Cr2O7.
Cr2O7-+6Fe2++14H+->2Cr3++6Fe3++7H2O
Calculate the percent KClO3 (FW = 122.55) in the sample.
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