A 0.58 kg ball is moving horizontally with a speed of 3.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.5 m/s. What is the magnitude of the change in linear momentum of the ball? Number i 5,51 Units kg-m/s or N-s

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

A 0.58 kg ball is moving horizontally with a speed of 3.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.5 m/s. What is the magnitude of the change in linear momentum of the ball?

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  - Number: [5.51]
  - Units: [kg⋅m/s or N⋅s] (dropdown selection)

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Transcribed Image Text:**Problem Statement:** A 0.58 kg ball is moving horizontally with a speed of 3.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.5 m/s. What is the magnitude of the change in linear momentum of the ball? **Submission Details:** - **Answer Box:** - Number: [5.51] - Units: [kg⋅m/s or N⋅s] (dropdown selection) - **Feedback:** - Your answer is partially correct. - **Additional Resources:** - eTextbook and Media link available. - **Hint:** - A section where hints may be available. - **Save Option:** - Save for Later button is present. - **Attempts:** - 2 of 5 attempts used. - Note: Using multiple attempts will impact your score. There is a 5% score reduction after attempt 3. **Action:** - To proceed, adjust the answer and click the "Submit Answer" button.
Expert Solution
Step 1

Given Data:

The mass of a ball is, m=0.58 kg

The initial velocity of a ball is, u=-3.8 m/s

The final velocity of a ball is, v=2.5 m/s

 

The expression for the change in linear momentum is,

p=mv-u...........(1)

Here, m is the mass, v is the final velocity, and u is the initial velocity.

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