Part AA 0.325 L flask filled with gas at 0.914 atm and 19 °C containsmol of gas.O 0.0148O 0.01249.4212.4O 80.7SubmitRequest Answer

The ideal gas equation is given by PV = nRT Given data Pressure inside the flask =0.914 atm V = volume of the flask = 0.325 L n = number of moles of gas = ? moles T= absolute temperature = 273+19 oC = 292 K and R is gas constant = 0.0821 liter-atm/mole-K Number of moles of gas, n = PVRT on substituting the given data in the ideal gas equation, Number of moles of gas, n =0.325×0.9140.0821×291 =0.0124 moles Result: number of moles of the gas = 0.0124 moles

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A 0.325 L flask filled with gas at 0.914 atm and 19 °C contains mol of gas. 0.0148 O 0.0124 O 40

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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