A 0.230 kg billiard ball that is moving at 3.70 m/s strikes the bumper of a pool table and bounces straight back at 2.96 m/s (80% of its original speed). The collision lasts 0.0200 s. (Assume that the ball moves in the positive direction initially.) (a) Calculate the average force (in N) exerted on the ball by the bumper. (Indicate the direction with the sign of your answer.) 1.532 (b) How much kinetic energy in joules is lost during the collision? (Enter the magnitude.) 0.566 (c) What percent of the original energy is left? 64

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**Example Problem: Billiard Ball Collision**

Consider a 0.230 kg billiard ball that is moving at 3.70 m/s when it strikes the bumper of a pool table and bounces straight back at 2.96 m/s (80% of its original speed). The collision lasts 0.0200 s. (Assume that the ball moves in the positive direction initially.)

### (a) Calculate the average force (in N) exerted on the ball by the bumper. (Indicate the direction with the sign of your answer.)

Given values:
- Mass of the ball, \( m = 0.230 \, \text{kg} \)
- Initial velocity of the ball, \( v_i = 3.70 \, \text{m/s} \)
- Final velocity of the ball, \( v_f = -2.96 \, \text{m/s} \) (the direction is negative since it bounces back)
- Time duration, \( t = 0.0200 \, \text{s} \)

Using the impulse-momentum theorem:
\[ F_{\text{avg}} = \frac{m(v_f - v_i)}{t} \]

Calculation:
\[ F_{\text{avg}} = \frac{0.230 \, \text{kg} \times (-2.96 \, \text{m/s} - 3.70 \, \text{m/s})}{0.0200 \, \text{s}} \]
\[ F_{\text{avg}} = \frac{0.230 \times (-6.66)}{0.0200} \]
\[ F_{\text{avg}} = \frac{-1.5318}{0.0200} \]
\[ F_{\text{avg}} = -76.59 \, \text{N} \]

Thus, the average force exerted on the ball by the bumper is:
\[ -76.59 \, \text{N} \]

### (b) How much kinetic energy in joules is lost during the collision? (Enter the magnitude.)

Using the kinetic energy formula:
\[ KE = \frac{1}{2}mv^2 \]

Initial kinetic energy:
\[ KE_i = \frac{1}{2} \times 0.230 \, \text{kg} \times (3.70 \, \text{m/s
Transcribed Image Text:**Example Problem: Billiard Ball Collision** Consider a 0.230 kg billiard ball that is moving at 3.70 m/s when it strikes the bumper of a pool table and bounces straight back at 2.96 m/s (80% of its original speed). The collision lasts 0.0200 s. (Assume that the ball moves in the positive direction initially.) ### (a) Calculate the average force (in N) exerted on the ball by the bumper. (Indicate the direction with the sign of your answer.) Given values: - Mass of the ball, \( m = 0.230 \, \text{kg} \) - Initial velocity of the ball, \( v_i = 3.70 \, \text{m/s} \) - Final velocity of the ball, \( v_f = -2.96 \, \text{m/s} \) (the direction is negative since it bounces back) - Time duration, \( t = 0.0200 \, \text{s} \) Using the impulse-momentum theorem: \[ F_{\text{avg}} = \frac{m(v_f - v_i)}{t} \] Calculation: \[ F_{\text{avg}} = \frac{0.230 \, \text{kg} \times (-2.96 \, \text{m/s} - 3.70 \, \text{m/s})}{0.0200 \, \text{s}} \] \[ F_{\text{avg}} = \frac{0.230 \times (-6.66)}{0.0200} \] \[ F_{\text{avg}} = \frac{-1.5318}{0.0200} \] \[ F_{\text{avg}} = -76.59 \, \text{N} \] Thus, the average force exerted on the ball by the bumper is: \[ -76.59 \, \text{N} \] ### (b) How much kinetic energy in joules is lost during the collision? (Enter the magnitude.) Using the kinetic energy formula: \[ KE = \frac{1}{2}mv^2 \] Initial kinetic energy: \[ KE_i = \frac{1}{2} \times 0.230 \, \text{kg} \times (3.70 \, \text{m/s
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