A 0.017-kg bullet is fired into a stationary block of wood of mass of 4.7 kg. The relative speed of the bullet with respect to the wood is zero after collision (The bullet becomes embedded on the block of wood). If the speed of the bullet before collision is 472 m/s, what is the kinetic energy of the bullet-plus-wood combination right after the collision? Assume no change in the potential energy of the system before and after the collision. Express your answer in two decimal places, in Joules.

A 4 kg block moving right at 6 m/s collides elastically with a 2 kg block moving right at 3 m/s. Calculate the final kinetic energy. What is the velocity of a 10 kg object move if an average power of 120 watts is used and the applied force is parallel to the surface? 1.22 m/s 12.2 m/s 0.82 m/s 102 m/s 82 m/s

A 0.01 kg bullet moves at a constant speed of 500 m/s and collides with a 1.5 kg wooden block initially at rest. The surface of the table is friction-less and 0.7 m above the floor level. After the collision the bullet becomes embedded into the block. The bullet-block system slides off the top of the table and strikes the floor. What is the resulting kinetic energy of the bullet and block system just before impact with the ground?

Current Attempt in Progress In the figure here, a stationary block explodes into two pieces L and R that slide across a frictionless floor and then into regions with friction, where they stop. Piece L, with a mass of 3.3 kg, encounters a coefficient of kinetic friction u = 0.45 and slides to a stop in distance d = 0.33 m. Piece R encounters a coefficient of kinetic friction µr = 0.52 and slides to a stop in distance de = 0.46 m. What was the mass of the block? HR – di Up Number i Unit eTextbook and Media GO Tutorial Save for Later Attempts: 0 of 8 used Submit Answer étv 80 DD F2 F3 F4 F6 FZ F8 F9 F10 F11 F5