A 0.00600 kg bullet traveling horizontally with speed 1.00 x 103 m/s strikes a 14.9 kg door, embedding itself 12.0 cm from the side opposite the hinges as shown in the figure below. The 1.00 m wide door is free to swing on its frictionless hinges. Hinge (a) Before it hits the door, does the bullet have angular momentum relative the door's axis of rotation? O Yes O No (b) If so, evaluate this angular momentum (in kg · m/s). (If not, enter zero.) 5.28 v kg m/s If not, explain why there is no angular momentum. This answer has not been graded yet. (c) Is mechanical energy of the bullet-door system constant in this collision? Answer without doing a calculation. O Yes O No (d) At what angular speed (in rad/s) does the door swing open immediately after the collision? 1.06 v rad/s (e) Calculate the total energy of the bullet-door system and determine whether it is less than equal to the kinetic energy of the bullet before the collision. (Enter your answers in J.) KE, - 2.79 KE, - 3000 (f) What If? Imagine now that the door is hanging vertically downward, hinged at the top, so that figure is a side view of the door and bullet during the collision. What is the maximum height (in cm) that the bottom of the door will reach after the collision?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 68P: Two astronauts (Fig. P10.67), each having a mass M, are connected by a rope of length d having...
icon
Related questions
icon
Concept explainers
Question

I need help with the last part

A 0.00600 kg bullet traveling horizontally with speed 1.00 × 103 m/s strikes a 14.9 kg door, embedding itself 12.0 cm from the side opposite the hinges as shown in the figure below. The 1.00 m wide door is free to swing on its frictionless hinges.
Hinge
(a) Before it hits the door, does the bullet have angular momentum relative the door's axis of rotation?
O Yes
O No
(b) If so, evaluate this angular momentum (in kg · m/s). (If not, enter zero.)
5.28
kg •
m?/s
If not, explain why there is no angular momentum.
This answer has not been graded yet.
(c) Is mechanical energy of the bullet-door system constant in this collision? Answer without doing a calculation.
O Yes
ON O
(d) At what angular speed (in rad/s) does the door swing open immediately after the collision?
1.06
rad/s
(e) Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision. (Enter your answers in J.)
KE,
2.79
KE,
3000
(f) What If? Imagine now that the door is hanging vertically downward, hinged at the top, so that the figure is a side view of the door and bullet during the collision. What is the maximum height (in cm) that the bottom of the door will reach after the collision?
1.9
cm
Transcribed Image Text:A 0.00600 kg bullet traveling horizontally with speed 1.00 × 103 m/s strikes a 14.9 kg door, embedding itself 12.0 cm from the side opposite the hinges as shown in the figure below. The 1.00 m wide door is free to swing on its frictionless hinges. Hinge (a) Before it hits the door, does the bullet have angular momentum relative the door's axis of rotation? O Yes O No (b) If so, evaluate this angular momentum (in kg · m/s). (If not, enter zero.) 5.28 kg • m?/s If not, explain why there is no angular momentum. This answer has not been graded yet. (c) Is mechanical energy of the bullet-door system constant in this collision? Answer without doing a calculation. O Yes ON O (d) At what angular speed (in rad/s) does the door swing open immediately after the collision? 1.06 rad/s (e) Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision. (Enter your answers in J.) KE, 2.79 KE, 3000 (f) What If? Imagine now that the door is hanging vertically downward, hinged at the top, so that the figure is a side view of the door and bullet during the collision. What is the maximum height (in cm) that the bottom of the door will reach after the collision? 1.9 cm
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Moment of inertia
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University