**Question 2:**A 4 kg ball attached to the end of a horizontal cord is rotated in a circle of radius 1 m on a frictionless horizontal surface. If the cord will break when the tension exceeds 90 N, what is the maximum speed the cord can have?---For this problem, the key concept is centripetal force, which is required to keep an object moving in a circular path. The tension in the cord provides this centripetal force and should not exceed 90 N to avoid breaking. The formula for centripetal force \( F_c \) is given by:\[ F_c = \frac{m \cdot v^2}{r} \]Where:- \( m \) is the mass (4 kg),- \( v \) is the speed,- \( r \) is the radius (1 m).By solving the equation \( \frac{m \cdot v^2}{r} \leq 90 \) N, you can find the maximum speed \( v \).

Mass of the ball, m = 0.4 kg Radius of the circle, r = 1 m Maximum tension, T = 90 N From…

A .4 kg ball attached to the end of a horizontal cord is rotated in a circle of radius 1 m on a frictionless horizontal surface. If the cord will break when the tension exceeds 90 N, what is the maximum speed the cord can have?

A .4 kg ball attached to the end of a horizontal cord is rotated in a circle of radius 1 m on a frictionless horizontal surface. If the cord will break when the tension exceeds 90 N, what is the maximum speed the cord can have?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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