College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Question 2:**

A 4 kg ball attached to the end of a horizontal cord is rotated in a circle of radius 1 m on a frictionless horizontal surface. If the cord will break when the tension exceeds 90 N, what is the maximum speed the cord can have?

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For this problem, the key concept is centripetal force, which is required to keep an object moving in a circular path. The tension in the cord provides this centripetal force and should not exceed 90 N to avoid breaking. The formula for centripetal force \( F_c \) is given by:

\[ F_c = \frac{m \cdot v^2}{r} \]

Where:
- \( m \) is the mass (4 kg),
- \( v \) is the speed,
- \( r \) is the radius (1 m).

By solving the equation \( \frac{m \cdot v^2}{r} \leq 90 \) N, you can find the maximum speed \( v \).
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Transcribed Image Text:**Question 2:** A 4 kg ball attached to the end of a horizontal cord is rotated in a circle of radius 1 m on a frictionless horizontal surface. If the cord will break when the tension exceeds 90 N, what is the maximum speed the cord can have? --- For this problem, the key concept is centripetal force, which is required to keep an object moving in a circular path. The tension in the cord provides this centripetal force and should not exceed 90 N to avoid breaking. The formula for centripetal force \( F_c \) is given by: \[ F_c = \frac{m \cdot v^2}{r} \] Where: - \( m \) is the mass (4 kg), - \( v \) is the speed, - \( r \) is the radius (1 m). By solving the equation \( \frac{m \cdot v^2}{r} \leq 90 \) N, you can find the maximum speed \( v \).
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