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Choices for the last requirement, "determine the approximate
a. 29%
b. 20%
c. 26%
d. 22%
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- Q1: For the machines indicated below. Consider i= 10% per year First cost Annual cost Salvage value Life duration Machine A 20,000 $ 5,000 $ 7,500 $ 3 Machine B 25,000 4,000 6,000 4 A- Draw cash flow diagram for each machine for one cycle of each project B- Draw cash flow diagram for each project considering the LCM life cycle (Hint: different project duration, need to have the LCM life cycle) C- Compare the machines to select best alternative one based on Present worth analysis method D- Repeat part B considering Future worth analysisYou are considering the following project. What is the NPV of the project? WACC of the project: 0.10 Revenue growth rate: 0.05 Tax rate: 0.40 Revenue for year 1: 13,000 Fixed costs for year 1: 3,000 variable costs (% of revenue): 0.30 project life: 3 years Economic life of equipment: 3 years Cost of equipment: 20,000 Salvage value of equipment: 4,000 Initial investment in net working capital: 2,000Determine the B/C ratio for the following project. First Cost P100, 000 Project life, years 5 Salvage value P10, 000 Annual benefits Р60, 000 Annual O and M Р22, 000 Interest rate, % 15
- A project is estimated to cost P120T, last 8 years & have a salvage value of P20T. The annual gross income is expected to average P50k & annual expenses is P5T. If capital is earning 10% determine if this is a desirable investment using annual cost method, what is the net cost. : a. 24,255.598 b. P24,756.951 c. 25,245.598 d. P27,535.412Compute the benefit cost ratio of the following project: Project cost = P80 000 Gross Income = P25000/year %3D Operating Cost = P6000/year Salvage value = 0 Life of project = 10 years %3D Rate of interest = 12%The cost data for two projects are given below. (a) Draw the cashflow diagram of Project 1. (b) Determine the better alternative using the annual cash flow analysis. Project 1 Project 2 $200,000 $180,000 24,000 Initial cost Net Annual Benefit 30,000 Salvage value Life in years 45,000 20,000 13 10 MARR 6%
- You are required to investigate the following project: The initial Investment at n=0 is $100,000. The project life is 10 years. Estimated annual operating cost : 34,000. The required minimum return on the investment :14%. The salvage value 8,000. What is the minimum annual revenues that should be generated to make the project worthwhile? 97842 52758 81921 45716 O O O OQ4. The cash flow details of a public project is as follows Initial cost =BD 210000 Annual operating cost = BD 10000 Worth of annual benefits = BD 12,000 Worth of annual disbenefits = BD 1245 Salvage value = BD 150000 Interest rate per year = 8% and useful lie = 30 Years Using benefit-cost ratio method and find out the economical acceptability of the public project. Use PW and AW methods to find out the equivalent worth of costs, benefits and disbenefits, also discuss why it is profitable(Use excel)5. The data below are estimated for a project study. į = 10% Plan A Initial Investment Annual Operating Cost Life Salvage Value Annual Revenue Plan B Initial Investment Annual Revenue Annual Disbursement Life Salvage Value P 35,000 P 6,450 4 years none 19,000 P 50,000 P 25,000 P 13830 8 years none Which plan would you recommend? Use Present Worth Method and 8 years of study period. Profit for Plan A = 9047.85 Profit for Plan B =9, 591.13
- Given a Project with the following data: First (initial) cost = JD 7000; Annual Operating cost= JD 1200; Salvage Value = JD 1500, i-8% per year, and 12 years. To Calculate the Equivalent Single Value (Eq. X) at the end of year 5, we use:A four-year project has an initial cost of $20 000, net annual cash inflows of $10 000, and a salvage value of $5 000. Which of the following gives the project's internal rate of return (i*)? -20 000(F/P, i*, 4) + 10 000 + 5 000 = 0 -20 000(A/P, i*, 4) + 10 000 + 5 000(A/F, i*, 4) = 0 -20 000(A/F, i*, 4) + 10 000 + 5 000(A/P, i*, 4) = 0 -20 000(P/F, i*, 4) + 10 000 + 5 000(A/F, i*, 4) = 01. Determine the B/C ratio for the following project. First Cost P100, 000 Project life, years 5 Salvage value P10, 000 Annual benefits P60, 000 Annual O and M P22, 000 Interest rate, % 15 Ans: B/C = 1.16