97. To determine the value of the definite integral: 3 x - 3 x² - 6x + 10 a. Complete the square of the denominator of the integrand: x² - 6x + 10 = (___ _ _)² + __ b. Determine the anti-derivative using an appropriate substitution: x - 3 √₁² x² - 6x + 10 3 dx = c. Use the anti-derivative to evaluate the definite integral: C dx x - 3 2 x² - 6x+10 -dx =

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