9.6.A) Classify the soil with the following properties according to the USCS.% passingDia (mm)1004.079.291.51002.00.84 0.4236.5 L.L-33%P.L-25%58.70.149 0.075

Given :- % passing with the corresponding Diameter of soil. Liquid limit, LL = 33% Plastic limit ,…

Answered: 9.6. A) Classify the soil with the…

9.6. A) Classify the soil with the following properties according to the USCS. % passing Dia (mm) 79.2 91.5 100 0.84 100 4.0 2.0 0.42 58.7 36.5 L.L=33% 0.149 0.075 P.L-25%

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: • AASHTO SOIL CLASSIFICATION (by AASHTO) AASHTO = American Association of scate Highway and…

Q: • AASHTO SOIL CLASSIFICATION (by AASHTO) AASHTO = American Association of state Highway and…

A: Group Index of soil is the number used to allude to the nature of soil utilized as subgrade material…

Q: Question 14 Classify the following soils using the Unified soil classification system. Give the…

A: Given data, Percentage of finer passing through No.4 sieve = 100 No.200 sieve = 77 Liquid limit…

Q: of Container of Container + Dry Soil of Dry Soil Sample 198 g 722 g 524 g Mass of Mass of Mass eter…

Q: Classify the following soils by using the Unified Soil Classification System. Give the group symbols…

Q: Using AASHTO Classification System, determine the following: (a) Group Index (b) Soil Classification…

Q: Refer to the figure below. The uniformly distributed load on the ground surface is Ao. Given: Ao =…

Q: 2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in…

A: Find the corresponding dry densities of the given water content results from Standard Proctor Test…

Q: Determine D10, D30, D60, Cu and Cc of the following soils.

A: Soil A Soil B Soil C sieve No. sieve size in mm % finer % finer % finer 4 4.75 84.231 100…

Q: Sieve Analysis Mass Retained Diameter The following (grams) are the Sieve No. (mm) B results of a…

A: Given We have Two types of soil samples One is -A Other one is - B We have to classify the soils…

Q: Yren wan given a sol sample which yelds the totowing passing percentage tor derent sieves Seve No.…

A: Solution: AASHTO System GI

Q: Using AASHTO Classification System, determine the following: (a) Group Index (b) Soil Classification…

Q: 1. AASHTO Classification for Soil A 2. Group Index for Soil A 3. Group Index for Soil B

A: 1. Soil A classification Soil A Percent finer No. 200 = 30 < 35 Soil A will be among A-1 or A-2…

Q: a. Classify soil A using AASHTO method. b. Classify soil B using AASHTO method c. Classify soil C…

Q: The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in…

A: The given data shows the result obtained from Standard Proctor Test. It is required to Determine…

Q: Which of the following nearly gives the %gravel of Soil B using AASHTO? which of the following…

Q: Q5: Classify the soil with the data in table below using USCS to find the followings 1- group symbol…

A: H

Q: (a) Sieve and hydrometer analysis for two soils are given in the following, calculate the amount of…

A: Unlike ordinary cement concrete, where different types and classes of hydraulic cement are used as a…

Q: 2. Determine the Unified Soil Classification System (USCS) classification for the following…

A: Unified soil classification system(USCS): (1) Classify the soil whether it is coarse or fine grained…

Q: PROBLEM NO. 2 A fined grained soil (no sand) is found to have a liquid limit of 70%, and a plastic…

Q: Sieve No. 4 10 40 200 LL PL Soil A 100 68.5 36.1 18.1 34.8 17.5 Soil B Percentage Passing 91.4 79.5…

Q: a soil if its bulk density is 125 lb/ft and it has a moisture content of 24 percent. The specific…

A: Given data : Moisture content (w%)=24% Bulk density (γBulk)=125 lb/ft3

Q: B. Classify the soils A and B, with the properties as shown below, according to USCS system. %…

A: The soil properties of Soil A and Soil B is given. We have to classify them as per USCS system.

Q: What is the soil type based on the USCS classification cent paing Sieve#4, 52% Per nt pass g…

A: Step1:Look at the % passing through sieve no 200=10<50%⇒COARSE GRAINED SOIL

Q: Sieve # Maas retained (gr) 4 0 10 11,5 16 11,7 20 12 30 12,9 40…

A: sieve mass cumulative weight reatained % cumulative weight 4 0 0 0 10 11.5 11.5 4.11 16…

Q: Soil A B No. 4 91 85 % Finer No. 200 58 32 Liquid Limit 30 25 Plastic Limit 12 19 Uniformity…

Q: The proportions of the solid particles in the soil determine the soil

A: The proportions of the solid particles in the soil determine the soil texture

Q: A silt clay soil has a plastic limit of 25 and a plasticity index of 30. 70 60 CH of 아 SO PIOLL-…

A: given Plastic limit (PL) = 25, Plasticity Index (Ip) = 30, Water content percent (W) = 35, a)…

Q: For the results obtained from the EX5! sieve analy sis. Classity the USCS. Given: LL-27っP.L0151)…

Q: Classify the soil using AASHTO. The liquid limit and plastic limit are found to be 30 and 20,…

A: iLook at the %passing through No 200 sieve :=20%<35% so Granular material

Q: * Standard Reference of Water Content Determination is ASTM D 2216 O D ASTM 5321 O ASTM D 7687 O…

A: Which is Standard Reference of Water Content Determination?

Q: 21. Classify the following soil according to USCS. Please present your steps logically Sieve opening…

Q: Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 84% ; No. 40- 71%…

Q: Classification and properties of soil in deatils

A: Soil is a mixture of mineral, gases, liquid, organism and organic matter which combinedly support…

Q: Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil…

A: given liquid limit= 60% and plastic limit =40% plasticity index=LL-PL Ip=LL-PLIp=60-40Ip=20%

Q: Classify the soil according to AASTHO classification and determine the Group Index in each case

A: The soil classification as per AASTHO is given below:

Q: For a given soil, the following are known: Sieve No. % Passing 4 200 Liquid Limit 33 70 30 Plastic…

A: Given Liquid limit, LL = 33% plastic limit, PL = 12% Percentage Passing seive number 4 = 70%…

Q: If gravel voulme conversion factor is like below and bedding layer should ,be compacted

Q: Given the liquid limit of soil equal to 70% and its plastic limit is 38% What will be the Liquidity…

Q: A sieve analysis test was performed for a dry soil sample with a total weight (490 gm). Sieve Mass…

A: classification of the soil is done to arrange the soils into different group on the basis of their…

Q: Classify soil A depicted in the table according to the AASHTO classification system. Sieve analysis-…

A: Classification of above given sample

Concept explainers

Soil engineering for highway design

Soil engineering is a part of geotechnical engineering that deals with the characteristics of soil. It also helps to understand the behavior of the soil in different conditions. The basic concepts of soil are studied to check the strength, compressibility, and porosity of the soil. This makes soil engineering an important topic for civil engineering.

Question

9.6.
A) Classify the soil with the following properties according to the USCS.
% passing
Dia (mm)
100
4.0
79.2
91.5
100
2.0
0.84 0.42
36.5 L.L-33%
P.L-25%
58.7
0.149 0.075

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Classify the following soils by the Unified soil classification system. Give the group na soil Soil 1 2 Sieve analysis (percentage finer) Liquid Plastic No. 4 No. 200 limit limit 98 28.5 33.2 22.6 95 10 30 22 D10 D30 8 D60 0.085 0.12 0.135 Q1)
Classify each soil according to ASSHTO classification system. Description Percent finer than No.10 Sieve SOIL A SOIL B SOIL C 83 100 48 Percent finer than No.40 Sieve 48 92 28 Percent finer than No.200 Sieve 20 86 6. Liquid Limit Plasticity Index N/A Non plastic 20 70 5 32
soil classification
Classify the group symbol of the soil by USCS using the data given below: Percent passing the #4 sieve 68 Percent passing the #200 sieve 22 Liquid Limit 34 Plastic Limit 17 Group of answer choices SM SW SP SC
The result of the particle-size analysis of a soil are as follows: Sieve No. % Passing 10 40 200 100 80 58 7. The liquid limit and plasticity index of the soil are 30 and 10, respectively. Classify the soil by AASHTO Classification system. а. А-4 (3) b. A-4(4) A-5(3) d. A-5(4) C.
Q2/ Classify the soil with the following properties according to the USCS Dia.(mm) 2.0 0.84 0.42 0.25 0.15 0.075 L.L= 40 P.L= 15 % passing 100 91.5 79.2 60 30 10
From the particle size distribution curve, about 61% of the oil is finer than 0.074 mm in diameter. The liquid limit and plastic limit of minus No 40 fraction of the soils are as follows: LL =26, PL= 20. Classify the soil using the USCS.a. CL-MLb. CL-MLc. SP-SCd. CH
Problem D: For problems 14 to 17. Classify the following soils by the AASHTO classification System. Description A D Percent finerthan No. 4 sieve 100 | 92 100 94 Percent finerthan No. 10 sieve 100 85 80 80 Percent finerthan No. 40 sieve 96 71 78 51 Percent finerthan No. 200 sieve 72 56 59 15 Liquid Limit Plasticity Index 16) Soil A is ? 58 35 42 26 23 19 13 12 a) A-7-5(19) b) A-2-6 (0) c) A-7-6 (18) d) A-7-5 (18) 17) Soil Bis ? a) A-6(13) b) A-7-5(0) c) A-6 (7) d) A-6 (8) 18) Soil Cis ? a) A-7-6(5) 19) Soil D is ? a) A-2-6(2) b) A-7-6 (8) c) A-7-6 (7) d) A-7-6(6) b) A-3 (0) c) A-2-6 (0) d) A-2-6 (2)
soil ضنتدوسي
ARectangular channel have a discharge 2.1 m3/sec Velocity equal 1.3m/sec,if the water depth equal to has the base find the dimensions of channel and the channel slope use n=0.02 / retry to Solve the problem by using the depth egual to dubole the base
For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
Classify the following soil by USCS classification system by giving the group symbol and the group name. % finer than No. 4: 71 % finer than No. 200: 11 LL: 32 PL: 16 Cu: 4.8 Cc: 2.9 Group Symbol is and the Group Name is