9.35 A twirler's baton is made of a slender metal cylinder of mass M and length L. Each end has a rubber cap of mass m and you can accurately treat each cap as a particle in this problem. Find the total moment of inertia of the baton about the usual twirling axis (per- pendicular to the baton through its center).

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Chapter11: Angular Momentum
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9.35, why is there a 1/12 ML^2 for M? Please draw a free body diagram, thanks!
9.34 Small blocks, each with mass m, are clamped at the ends and
at the center of a light rod of length L. Compute the moment of iner-
tia of the system about an axis perpendicular to the rod and passing
through a point of the length from one end. You can ignore the
moment of inertia of the light rod.
]=mr²
t
J= m ( 4 ) ² + m ( 2 ) ² + (1²
I= ALL': gal
MLC
9mL?
1/m2²
16
16
16
9.35 A twirler's baton is made of a slender metal cylinder of mass
M and length L. Each end has a rubber cap of mass m and you can
accurately treat each cap as a particle in this problem. Find the total
moment of inertia of the baton about the usual twirling axis (per-
pendicular to the baton through its center).
I= mr²
m ( = 1² + m ( = 1²
me²
me me ² - 2m ²²
4
4
Transcribed Image Text:9.34 Small blocks, each with mass m, are clamped at the ends and at the center of a light rod of length L. Compute the moment of iner- tia of the system about an axis perpendicular to the rod and passing through a point of the length from one end. You can ignore the moment of inertia of the light rod. ]=mr² t J= m ( 4 ) ² + m ( 2 ) ² + (1² I= ALL': gal MLC 9mL? 1/m2² 16 16 16 9.35 A twirler's baton is made of a slender metal cylinder of mass M and length L. Each end has a rubber cap of mass m and you can accurately treat each cap as a particle in this problem. Find the total moment of inertia of the baton about the usual twirling axis (per- pendicular to the baton through its center). I= mr² m ( = 1² + m ( = 1² me² me me ² - 2m ²² 4 4
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