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The given wood joint is made from an Apitong lumber (Species Group II). It is supported with 4 bolts. Determine minimum capacity of one bolt and minimum diameter of the bolts if it is subjected to P=15kN and angle = 22 degrees. Both members have thickness of 75 mm and consider single shear.
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- Sawed lumber or surfaced lumber is planed of cleaned on at least one edge, for four side it is designated as a. S1S b. S2S c. S4S d. None of the aboveA beam is made of four planks glued together. Knowing that the vertical shear in the beam is V = 500 N, determine the minimum required shear strength Tg for the glue. molinu sib boto nsini odi i Resua sode inn 50 mm, 50 mm 50 mm B D 150 mm 50 mm 150 mm 50 mmDetermine the maximum compressive force that can be exerted on the wood by the washer and determine the tensile stress that develops in the threaded area of the anchor bolt if the connection is tightened to the maximum compressive force.
- Based on the discussed defects of wood, which of these do you think acceptable forconstruction? Defend your answerThe two pieces of wood, 2 in. by 4 in., are glued together along the 40° joint. Determine the maximum safe axial load P that can be applied if the shear stress in the glue is limited to 250 psi.The built-up beam wooden above is subjected to a horizontal shear force, V, as shown. Assume that the beam dimensions are drawn to scale. Also assume that the nails attaching the three pieces of the cross-section allow it to act as a single member. Which of the following best explains why we cannot analyze the shear stresses in this beam with the techniques covered in this class (at least, so far)? The shear force is not "transverse" O Wood cannot be loaded perpendicular to the grain The shear force is not acting along a line of symmetry of the cross-section We can only deal with vertical shear forces
- The wood in the image below is ... O a. through sawn O b. cant sawn O C. O d. flat sawn quarter sawnTwo pieces of wood are glued together, find the maximum load which the glued wood could carry that must not exceed 12 MPa normal stress and 7 MPa shear stress. P 30° P 100 mm Glued Section 100 mmRequired information A composite beam is made by attaching the timber and steel portions shown with bolts of 12-mm diameter spaced longitudinally every 200 mm. The modulus of elasticity is 10 GPa for the wood and 200 GPa for the steel. The vertical shear is 4.4 kN. 12 mm 250 mm 12 mm 150 mm- Determine the average shearing stress in the bolts. (Round the final answers to two decimal places.) The average shearing stress in the bolts is MPa.
- Compute for the Modulus of Elasticity of the Wood if the Clear Span Length is 2300 mm, applied load is 10lbs and the deflection of the wood is about 16.5mm. Moment of Inertia of the wood is 2.75x105 mm4 a 2.63 GPa b 2.49 GPa c 2.59 GPa d 2.74 GPaCompute for the Modulus of Elasticity of the Wood if the Clear Span Length is 2300 mm, applied load is 10lbs and the deflection of the wood is about 16.5mm. Moment of Inertia of the wood is 2.75x105 mm4 o 2.59 GPa o 2.49 GPa o 2.74 GPa o 2.63 GPaWhich of the following is used for cutting wood? Select one: O a. End Plier Ob. Bench Vise O C. Bolt Clipper Od. Band saw
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