*9. ssm Two forces F, and F, are applied to an object whose mass is 8.0 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.50 m/s². However, when F. points due east and FB points due west, the acceleration is 0.40 m/s², due east. Find (a) the magnitude of F, and (b) the magnitude of Fp.

When Two forces FA and FB are applied to an object whose mass is 9.15 kg. The larger force is FA. both forces point due east, the object's acceleration has a magnitude of 0.784 m/s². However, when FA points due east and FB points due west, the acceleration is 0.420 m/s², due east. Find (a) the magnitude of FA and (b) the magnitude of FB. (a) Number i (b) Number i Units Units

Two forces É, = (81.24i – 26.83j) N and É, = (27.41i - 80.52j) N are exerted on a particle. The particle's mass is 23.21 kg. (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a = m/s? (b) What are the magnitude and direction of the acceleration? magnitude |m/s2 direction counterclockwise from the +x axis

Three forces acting on an object are given by F₁ = (−2.2î + 6.85ĵ) N, F₂ = (4.75î – 1.25ĵ) N, and F3 = (-401) N. The object experiences an acceleration of magnitude 3.80 m/s². (a) What is the direction of the acceleration? 98.50 X Note that the direction of the acceleration is the same as the direction of the net force.° (counterclockwise from the +x-axis) (b) What is the mass of the object? 9.964 kg (c) If the object is initially at rest, what is its speed after 11.0 s? 41.8 m/s (d) What are the velocity components of the object after 11.0 s? (Let the velocity be denoted by v.) ✓ = -41.34 m/s +6.18