MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Question 11arrow_forward1. Suppose you are a technician, whose repair time on a given job is said to follow an exponential distribution with expected time θ = 3 hours. You have 5 independent jobs lined up (you complete them sequentially, one by one). a. What is the probability of taking exactly 2 hours to finish a given job? b. What is the probability it will take more than 2 hours on a given job? c. You are on a given job and you already have been working for 1 hour. What is the probability it will at least an additional 2 hours to complete this job?arrow_forwardEx. A lottery ticket with two equally likely outcomes:(1) You win $2 (2) You win $0Let W be the amount won from the lottery. E[W] = 1VAR(W) =???arrow_forward
- Q. 1 It is estimated that 80% of emails are spam emails. Some software has been applied to filter these spam emails before they reach our inbox. A certain brand of software claims that it can detect 99% of spam emails, and the probability for a false positive (a non-spam email detected as spam) is 5%. Now if an email is detected as spam, then what is the probability that it is in fact a non-spam email? event A: email is spam; event B: email is detected as spam. Assume thatarrow_forwardNeed help with this practice problemarrow_forwardExample 7.40: You set out on a walk with three possible locations, denoted locations 1, 2 and 3. The probabilities of travelling from a specified location to the next are given by Solution. If you know that you started in location 3, what is the probability that you end up at location 1 after two time periods? Using the above equation, we get To solve this we use the equation Xn+1 = AXn. Given that you began in location 3, the initial state vector is and subsequently Exercise X₁ = AX0 Probability = A = = X₂ = AX₁ 0.5 0.2 0.4 0.4 0.6 0.1 0.1 0.2 0.5 = Xo 0 0.5 0.2 0.4 0.4 0.6 0.1 0.2 0.5 0.1 ][ Therefore the probability of ending up in location 1 after two time periods is 0.42. 0.5 0.2 0.4 0.4 0.6 0.1 0.1 0.2 0.5 1 0.4 0.1 = 0.5 0.4 0.1 0.5 = 0.42 0.27 0.31 Refer to the example above. If you know that you started in location 2, what is the probability that you will end up at location 1 after one time period?arrow_forward
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