9. A child has a type C) A) One of the parents could be type O B) One of the parents could be A D) One of the parents could be Ab 10. Short hair (S) is dominant to long hair (s). If a short-haired animal of unknown origin is crossed with a long-haired animal and they produce one long-haired and one short-haired offspring, this would indicate that A) the short-haired animal was pure-breeding. B) the short-haired animal was not pure-breeding. C) the long-haired animal was not pure-breeding. D) the long-haired animal was pure-breeding. la orpe with two alleles. When a homozygous brown-eyed If the

9. A child has a type C) A) One of the parents could be type O B) One of the parents could be A D) One of the parents could be Ab 10. Short hair (S) is dominant to long hair (s). If a short-haired animal of unknown origin is crossed with a long-haired animal and they produce one long-haired and one short-haired offspring, this would indicate that A) the short-haired animal was pure-breeding. B) the short-haired animal was not pure-breeding. C) the long-haired animal was not pure-breeding. D) the long-haired animal was pure-breeding. la orpe with two alleles. When a homozygous brown-eyed If the

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 18CTQ: Could an individual with blood type O (genotype ii) be a legitimate child of parents in which one...

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1) In pea plants, round seeds are dominant over wrinkled seeds. A Yellow seeded plant is crossed with a green seeded plant and the resulting cross produces 35 seeds. 12 of the seeds are yellow and 23 of the seeds are green. What are the genotypes of the parent plants? 2) In humans, blood type is inherited based on multiple alleles in which type A and type B are dominant to type O. A man who is type O, whose mother was type B, marries a woman who is type AB. What is the probability that they will produce a child that is type B? 3) In Guinea pigs black fur is dominant over white fur and smooth fur is dominant over rough fur. A heterozygous black, heterozygous smooth furred guinea pig mates with a white, heterozygous smooth furred guinea pig. Determine the phenotypic ratio for the predicted offspring from this crossing
1) Short hair in rabbits (R) is dominant over long hair (r). The following crosses are carried out, producing the progeny shown. Give the most likely genotypes of the parents in each cross. (Tabulate your answers). PARENTS a) short x short b) short x long c) short x long PROGENY 4 short and 2 long 12 short 3 short and 1 long
A man with blood type A (whose mother was blood type O) has children with a woman that has blood type AB. The man and the woman are also heterozygous for the H antigen. What is the probability that they will have a child with blood type A? A) 0 B) 1/8 C) 3/8 D) 1/2 E) 3/4
1. Given the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked recessive and b) X-linked dominant in order to determine what is the mode of transmission of this trait. Disease allele = XA or Xa, depending on mode of transmission of the disease respectively. *Unaffected/No carrier-Normal Unaffected X chromosome = X I 11 * 1 2 1 2 3 a) X-linked recessive 11x12 III 2 genotype (circle one): XY 4 XAXA 2 3 5 Xaya *4 6 7 8 b) X-linked dominant 11x12 XAY Xay
A child with AB+ blood is born to a mother that has A- blood. Which of the following paternal phenotypes is possible? 1. A positive 2. B positive 3. O positive 4. A negative
10- A man with X-linked color blindness marries a woman with no history of color blindness in her family. The daughter of this couple marries a normal man, and their daughter also marries a normal man. What is the chance that this last couple will have a child with color blindness? Assume the chance to have a daughter or a son is equal. a) 3/8 b) 1/8 C) 1/16 d) 3/4 02040 e) 1/4 Boş bırak
a. In a type of plant, pink flowers (P) is dominant over white flowers (p), and tall (T) is dominant over short (t). Determine the genotypes of the parents in the following cross: Pink, tall x pink, short O / pink, tall: /s pink, short: /s white, tall: / white, short Genotypes: () (ii) Phenotypes: Pink, tall Pink, short b. A woman has blood type A MM. She has a child with blood type O MN. Which of the following men could not be the child's father? Explain your reasoning. Man Blood type Peter O NN Rob AB MN Doug B MN Simon A NN Mike АВ М
2.) A tall green pea plant (TtGg) is crossed with a Short yellow pea plant (ttgg). FOIL each parent’s genotypes: tall green pea plant (TtGg) short white pea plant (ttgg) X MICHELLE CRISTINO - DI. How many of the 16 offspring are: tall & green tall & white short & green short & white
A P cross of AAbb x aaBB is performed. An F1 offspring is crossed with an individual that is aabb. Determine which two of the following are the recombinant phenotypes. 1. Recessive a, recessive b 2. Dominant A, recessive b 3. Recessive a, dominant B 4. Dominant A, dominant B
1. Black fur (B) in guinea pigs is dominant over white fur (b). A homozygous black and a heterozygous black guinea pig are crossed. a) Complete the Punnett Square (it is a google drawing so you will have to double click it to go to the drawing and type in and around the square). b) What are the possible phenotypes of the offspring of this cross, and what is the chance (probability) of getting each phenotype? c) Is it possible for the recessive allele (b) to show up in future generations? Justify (explain) your answer.
A couple consulted a genetic counselor and they found out the following: Basha: A blood type, blue eye color, normal skin condition, carrier of cystic fibrosis gene, and carrier of hemophilia gene Popoy: B blood type, has brown eye color, normal skin condition, carrier of cystic fibrosis gene and negative to hemophilia. Clues for the table: • Blood Type: The probability that they’ll have an offspring with blood type the same as Popoy is 25% only • Eye Color: The probability that they’ll have an offspring with brown eye color is 75%. • Skin condition: The probability that their offspring will be an albino is 25% What is the probability that the offspring will have/ be: A. a girl with all the same phenotype as her mother. B. 2 girls with neither the blood type of the parents. C. 2 boys with normal skin color and carrier of cystic fibrosis gene; 1 girl with normal skin color and negative to cystic fibrosis. D. 2 girls carrier of both cystic fibrosis gene and hemophilia, a boy † positive…
O. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S F