9 What neutral atom are tellurium, iodine, cesium, and barium ions isoelectric with? 10 Arrange the following set of ions in increasing (smallest to largest atomic radius: a. P-3, S-2, Cl-, K+. b., Te, Ru, Li, Pd.

Write the full electron configuration of the ion oxide, O2- You can indicate superscript through the ^ symbol (e.g. 3s2 could be written as 3s^2) or use the superscript text formatting tool above.

Which of the following species is diamagnetic (not paramagnetic):  Li, V, Ni, Zn, Fe2+       Select one: a.     Fe2+   b.   V   c. Li d.   Ni   e.   Zn

4. Which one of the following elements has a +2 ion with 2 unpaired electrons? Be Ge Co Ni Fe

Identify each element below. „La).[Ar.].4s?3 (b) [Xe] 6s²4A45d2 (c) [Xe] 6s²5d104f146p3

Please answer very soon

18. Write the full and abbreviated electron configurations for molybdenum. How many core and valence electrons does it have? Isoei gniwallot srit shA: 36; 6

Which of the following is the electron configuration of the iron(II) ion (Fe2+)?  Select one: a. [Ar]4s23d9 b. [Ar]4s23d2 c. [Ar]4s13d5 d. [Ar]3d6 e. [Ar]3d5 Clear my choice

Which of the following represent the proper long hand form electron configuration of molybdenum, Mo, using the building-up principle?   answer choices A. [Kr] 4d4 5s2 B. [Kr] 5s2 4d4 C. 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2 4d4 D. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d4 E. 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d4 5s2

Which of the options below provides a reason why the covalent radius of hafnium (1.44 Å) is less than that of zirconium (1.45 Å), even though the element above it in the periodic table? A. Between Zr and Hf lies the 4d10 configuration due to the transition metals. This leads to much greater Z* because the d electrons are so poor at shielding. Thus Hf is smaller than expected for an element in a higher shell than Zr, called the Scandide contraction. B. Hf being below Zr suggests that it will have a smaller atomic radius because the trend shows a decrease going down a group. C. Hf is below Zr and has a smaller ionisation energy, electron affinity and electronegativity compared to Zr. This reduces its atomic radius, thus leading to it having a smaller atomic radius compared to that of Zr. D. Between Zr and Hf lies the 4f14 configuration due to the Lanthanides. This leads to much greater Z* because the f electrons are so poor at shielding. Thus Hf is smaller than expected for an element in…