
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:9) The massless rod is 1.6 m long, and the masses are 3.0 kg each. Find the rotational inertia of the rod as
it spins about its midpoint. How could you increase the rotational inertia?
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- 7. A bicyclist starting at rest produces a constant angular acceleration of 1.70 rad/s2 for wheels that are 34.0 cm in radius. (a) What is the bicycle's linear acceleration (in m/s2)? (Enter the magnitude.) (b) What is the angular speed of the wheels (in rad/s) when the bicyclist reaches 11.2 m/s? (c) How many radians have the wheels turned through in that time? (d) How far (in m) has the bicycle traveled?arrow_forwardA constant horizontal force of 10 N is applied to a wheel of mass = 10 kg and radius of 0.3 m. The center of mass of the wheel has an acceleration of 0.48 m/s/s. a) Determine the magnitude of the friction force acting on the wheel. b) Determine the magnitude of the rotational inertia if the linear acceleration were 0.48 m/s/s. You will have to recalculate the friction force.arrow_forward18) Consider an adult and a child riding their bikes. The adult's bicycle has tires with an outer diameter of 700 centimeters. The child's bicycle has tires with an outer diameter of 350 centimeters. The adult bicycle's tires are rotating with an angular velocity of 4.0 radians per second. If the child cyclist is traveling along the road at the same speed as the adult, then what angular velocity must the child's bicycle's tires be rotating at? [Assume the tires are rotating without slipping as the cyclists ride]. A) 1.0 radians second per B) 2.0 radians per second C) 4.0 radians per second D) 8.0 radians per second E) 16.0 radians per second abnoose e Garrow_forward
- 2. A 20-kg sphere 0.05 m in radius starts from rest and rolls (without slipping) 8.0 m down a ramp that is inclined at 30° with the horizontal. (a) What is the angular speed of the sphere at the bottom of the slope if it starts from rest? (b) How much rotational kinetic energy does the sphere have at the bottom of the slope? (c) How much translational kinetic energy does the sphere have at the bottom of the slope?arrow_forwardI) A revolving door consists of a four identical panels mounted to a solid column. Each panel has a mass of 15 kg. The solid column has a mass of 20 kg with a radius of 250m. Find the rotational inertia about an axis that runs through the center of the solid column (the dashed line). 910 m 2.20 m Top down view: R = 250 m 910 marrow_forward3) Timmy (m, = 30.0 kg) is standing at the center of a merry-go-round that is spinning at 5.00 rad/s. The merry-go-round can be modeled as a disk with a diameter of 4.00 m and a mass of 50.0 kg, rotating on a frictionless axle though its center. He then walks to the edge of the merry-go-round. What is the new angular speed of the merry-go-round?arrow_forward
- A wheel has a radius of 0.1m and a moment of inertia of 4.00 kg-m2 starts from rest and accelerates under a constant torque of 12.0 N-m for 4.00 s. a) What is the wheel’s rotational kinetic energy at the end of 4.00 s? b) How far has the wheel rolled at the end of 4.00s?arrow_forward5) A torque of 35.3 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 10.1 rad/s. After 5.90 s the directed force is removed, and the wheel comes to rest 59.4 s later. (a) What is the wheel's moment of inertia (in kg · m2)? _kg · m2 (b) What is the magnitude of the torque caused by friction (in N · m)? _ N · m (c) From the time the directed force is initially applied, how many revolutions does the wheel go through? _ revolutionsarrow_forward
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