I looked up this problem for help and am confused with the part i circled in red. im blanking. why use the (4*3)/3(pi) and in the A4 (4*1)/3(pi)? February 28, 2022Assignment 5Alfonso SernaProblem:Find: Locate the centroid of the*9-64. Locate the centroid (x, y) of the shaded area.shaded area.yGiven: X -Z A:X;Ź Aiy= Ź Ai Yi1 in.- 3 in. 3 in.-AiProb. 9-64Ai= 3(3)/4.5in/23 x3=191n?Az=3%3Dt.5 y= 323X.(-3) +()2=1.5-4SubtractAy= TTp?_(314) )in1.57079637744Xg= /4X33TJ212. S6637061X =09.4247779614 4IT T 9.424779961y = 4x1ラ|, 273 23 9545- 0,4244131816Ž AiXi=(4.5)-4)- -18(9) 61.5)--13.5(2.ou5X1.2732395us}8,9954 Gdoz+ (1.570796327)(0) = cΣΑ:E A,Y.(4.5)(1)(a)(.5) 13.5(7,065%1.273.)9+ f1.920796327|(0.4244131816)4.5+9+7.065+4,5Glist)273239 545)8.9954Gl67)189942ī 1926.33-22.S0456261y=26,33X = - 22, s0436261 -,184812114-1.38578941919E 1.39-1.18Solution: x=-1.18in, y=1.39in3.2.

Answered: Image /qna-images/answer/b0432254-9cdf-44eb-b997-8c4686d142e7.jpg

Answered: *9-64. Locate the centroid (, y) of the…

*9-64. Locate the centroid (, y) of the shaded area. y 1 in. 3 in 3 in. 3 in. Prob. 9-64 Ai= 3(3)/4.0in/ 3. 2 3 =(-3)+()- - y= 2)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Site Plan Requirements

A site plan (also known as a plot plan) is a diagram or process to show the proposed improvements on an existing property. A site plan is important, as it provides information regarding the landscape features of a given plot of land. Zoning is done or can be understood with the help of a site plan.

Question

I looked up this problem for help and am confused with the part i circled in red. im blanking. why use the (4*3)/3(pi) and in the A4 (4*1)/3(pi)?

February 28, 2022
Assignment 5
Alfonso Serna
Problem:
Find: Locate the centroid of the
*9-64. Locate the centroid (x, y) of the shaded area.
shaded area.
y
Given: X -Z A:X;
Ź Ai
y= Ź Ai Yi
1 in.
- 3 in. 3 in.-
Ai
Prob. 9-64
Ai= 3(3)
/4.5in/
2
3 x3=191n?
Az=
3
%3D
t.5 y= 3
2
3
X.
(-3) +()
2=1.5
-4
Subtract
Ay= TTp?_(314) )
in
1.570796377
4
4
Xg= /4X3
3TJ
2
12. S6637061
X =0
9.424777961
4 4
IT T 9.424779961
y = 4x1
ラ
|, 273 23 9545
- 0,4244131816
Ž AiXi=
(4.5)-4)- -18
(9) 61.5)--13.5
(2.ou5X1.2732395us}8,9954 Gdoz
+ (1.570796327)(0) = c
ΣΑ:
E A,Y.
(4.5)(1)
(a)(.5) 13.5
(7,065%1.273.)9
+ f1.920796327|(0.4244131816)
4.5+9+
7.065+
4,5
Glist)
273239 545)8.9954
Gl67)
189942
ī 19
26.33
-22.S0456261
y=26,33
X = - 22, s0436261 -,184812114
-1.3857894
19
19
E 1.39
-1.18
Solution: x=-1.18in, y=1.39in
3.
2.

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