Follow my table sokve correct SOLUTIONs *9-64. Locate the centroid (x, y) of the shaded area.3 in.1 in.-3 in.-y3 in.Prob. 9-64-X 8:31upper section :=0Section Area (in) X (in) ū (in) AX (in ³) Ay (in²³)1265X(3) -45 7/3 (3)-2 1/3 (3)-194.540.513.551.419231/2 cw pg. 496 (9-4)Compute the centroidal moment ofinertia.2-129 1.5+3.45 1.54 (3)3TT4(1)3114-²/₂2(343)37119-+60.34K/s il O61-9.42 -0.6791.49 26.33X = 91.47 = 4.82 in (from y-axis)19y = 2633 = 1.39 in (from X-axis)D88%

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Answered: *9-64. Locate the centroid (x, y) of…

Engineering

Civil Engineering

*9-64. Locate the centroid (x, y) of the shaded area. y 3 in. 1 in. -3 in. 3 in. Prob. 9-64 X

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Follow my table sokve correct SOLUTIONs

*9-64. Locate the centroid (x, y) of the shaded area.
3 in.
1 in.
-3 in.-
y
3 in.
Prob. 9-64
-X

8:31
upper section :
=0
Section Area (in) X (in) ū (in) AX (in ³) Ay (in²³)
1265X(3) -45 7/3 (3)-2 1/3 (3)-1
9
4.5
40.5
13.5
51.41
9
2
3
1/2 cw pg. 496 (9-4)
Compute the centroidal moment of
inertia.
2
-12
9 1.5+3.45 1.5
4 (3)
3TT
4(1)
311
4-²/₂2
(343)
371
19
-+6
0.34K/s il O
6
1-9.42 -0.67
91.49 26.33
X = 91.47 = 4.82 in (from y-axis)
19
y = 2633 = 1.39 in (from X-axis)
D
88%

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Step 1: Given data

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Step 2: Finding the areas and centroidal distance of each section:-

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Step 3: Locating the centroids ( X,Y) of the given shared area:-

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