Homework Help is Here – Start Your Trial Now!
Math
Calculus
(9) 10F -5 -10 -10F O f(x) = -2x + 4 -2x2 O f(x) = 7x o f(x) = - 3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 %3D o Rx) = - + x2 - o Fx) = x5 - 2x3 +* (b) y (f) y (h) y y 10F 10- 10F 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 5x2 o f(x) o f(x) = - o (x) = - x* + 5x? * + 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - Rx) = - + x2 - o f(x) = - x + x2 - 4 + x2 O (x) 4 O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. o Fx) = x - 2x3 + * O (x) = O f(x) - 5

(9) 10F -5 -10 -10F O f(x) = -2x + 4 -2x2 O f(x) = 7x o f(x) = - 3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 %3D o Rx) = - + x2 - o Fx) = x5 - 2x3 +* (b) y (f) y (h) y y 10F 10- 10F 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 5x2 o f(x) o f(x) = - o (x) = - x* + 5x? * + 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - Rx) = - + x2 - o f(x) = - x + x2 - 4 + x2 O (x) 4 O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. o Fx) = x - 2x3 + * O (x) = O f(x) - 5

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 58E
See similar textbooks
icon
Related questions
Question

Match the polynomial function with its graph. 5 graphs in total. First three have been removed as they were answered in a previous bartleby question of mine. Thank you.

(9) 10F -5 -10 -10F O f(x) = -2x + 4 -2x2 O f(x) = 7x o f(x) = - 3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 %3D o Rx) = - + x2 - o Fx) = x5 - 2x3 +* (b) y (f) y (h) y y 10F 10- 10F 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 5x2 o f(x) o f(x) = - o (x) = - x* + 5x? * + 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - Rx) = - + x2 - o f(x) = - x + x2 - 4 + x2 O (x) 4 O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. o Fx) = x - 2x3 + * O (x) = O f(x) - 5
Transcribed Image Text:(9) 10F -5 -10 -10F O f(x) = -2x + 4 -2x2 O f(x) = 7x o f(x) = - 3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 %3D o Rx) = - + x2 - o Fx) = x5 - 2x3 +* (b) y (f) y (h) y y 10F 10- 10F 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 5x2 o f(x) o f(x) = - o (x) = - x* + 5x? * + 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - Rx) = - + x2 - o f(x) = - x + x2 - 4 + x2 O (x) 4 O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. o Fx) = x - 2x3 + * O (x) = O f(x) - 5
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 6 steps with 6 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Transcendental Expression
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
Calculus For The Life Sciences
Calculus For The Life Sciences
Calculus
ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,
Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS