8(k+1)-4 8(n+1)-4 4 8k-4 is term to both sides of the equation. 4+12+20++ (8k-4)= 4k² +20++ (8k-4)+ = 4K² + pt simplify.)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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To continue the proof by induction, begin with 4 + 12 + 20 + ... + (8k − 4) = 4k² which is assumed to be true, and add the k + 1 term to both sides of the formula. What is this term?
A. 8(k+1)-4
B. 8(n+1)-4
C. 4
D. 8k-4
Add this term to both sides of the equation.
= 4k²
4K²
4 + 12 + 20+...+(8k-4)
4 + 12 + 20+...+(8k − 4) +
(Do not simplify.)
= 4k
+
Transcribed Image Text:To continue the proof by induction, begin with 4 + 12 + 20 + ... + (8k − 4) = 4k² which is assumed to be true, and add the k + 1 term to both sides of the formula. What is this term? A. 8(k+1)-4 B. 8(n+1)-4 C. 4 D. 8k-4 Add this term to both sides of the equation. = 4k² 4K² 4 + 12 + 20+...+(8k-4) 4 + 12 + 20+...+(8k − 4) + (Do not simplify.) = 4k +
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