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8х, + х2 — хз — 8 2x1 + x2 + 9x3 = 12 X1 - 7x2 + 2x3 = -4 Solve equation system by using SOR method (w=1.1) for 3 iterations. (Use six decimal digits.)

8х, + х2 — хз — 8 2x1 + x2 + 9x3 = 12 X1 - 7x2 + 2x3 = -4 Solve equation system by using SOR method (w=1.1) for 3 iterations. (Use six decimal digits.)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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please note that the initial value is (0.0.0)

8x1 + x2 – X3 = 8 2x1 + x2 + 9x3 = 12 X1 — 7x2 + 2хз — — 4 Solve equation system by using SOR method (w=1.1) for 3 iterations. (Use six decimal digits.)
Transcribed Image Text:8x1 + x2 – X3 = 8 2x1 + x2 + 9x3 = 12 X1 — 7x2 + 2хз — — 4 Solve equation system by using SOR method (w=1.1) for 3 iterations. (Use six decimal digits.)
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