8.5 an 250 kN 250 kN 250 kN B D E 0.9 m'0.9 m 0.9 m 0.9 m Fig. P8.5

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Can you solve 8.5 please. Show all work and please do the static analysis for 8.5 like shown in the example.
8.5 and 8.6 (a) Knowing that oa = 160 MPa and Tall = 100 MPa, select
the most economical metric wide-flange shape that should be used
to support the loading shown. (b) Determine the values to be expected
for am, Tm, and the principal stress omax at the junction of a flange
and the web of the selected beam.
250 kN 250 kN 250 kN
|275 kN
В
B
D
E
A
D
275 kN
3.6 m
0.9 m
0.9 m
0.9 m
0.9 m
1.5 m
1.5 m
Fig. P8.5
Fig. P8.6
Transcribed Image Text:8.5 and 8.6 (a) Knowing that oa = 160 MPa and Tall = 100 MPa, select the most economical metric wide-flange shape that should be used to support the loading shown. (b) Determine the values to be expected for am, Tm, and the principal stress omax at the junction of a flange and the web of the selected beam. 250 kN 250 kN 250 kN |275 kN В B D E A D 275 kN 3.6 m 0.9 m 0.9 m 0.9 m 0.9 m 1.5 m 1.5 m Fig. P8.5 Fig. P8.6
Example
A W10 x 39 rolled-steel beam supports a load P as shown. Knowing that P = 45 kips, a = 10 in., and
Gall = 18 ksi, determine (a) the maximum value of the normal stress om in the beam, (b) the maximum value of
the principal stress Omax at the junction of the flange and web, (e) whether the specified shape is acceptable as far
as these two stresses are concerned.
P
P
|D
|B
-10 ft
Static Analysis
Static Anoly sis
Z f:o Ays - 2 Pr + Bys = 0
-a PE - (a+L)PR + (2a+L) BR =0
-RarL)P+(2a +L)B =0
B= P
Ay=P
Transcribed Image Text:Example A W10 x 39 rolled-steel beam supports a load P as shown. Knowing that P = 45 kips, a = 10 in., and Gall = 18 ksi, determine (a) the maximum value of the normal stress om in the beam, (b) the maximum value of the principal stress Omax at the junction of the flange and web, (e) whether the specified shape is acceptable as far as these two stresses are concerned. P P |D |B -10 ft Static Analysis Static Anoly sis Z f:o Ays - 2 Pr + Bys = 0 -a PE - (a+L)PR + (2a+L) BR =0 -RarL)P+(2a +L)B =0 B= P Ay=P
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