8) Find the mixed strategy Nash equilibrium of the following normal form game. Player 2 T1 T2 T3 S1 Player 1 2, 3 3, 5 1, 1 S2 1, 4 4, 3 0, 5 Player 1 attaches probability (S1, S2) = (, 5) and Player 2 attaches probability (T1, T2, T3) = ( 2. Player 1 attaches probability (S1, S2) = () and Player 2 attaches probability (T1, T2, T3) = (q1, 42, 1 – q1 – 92) where q1 = , and 0 < 42 s Player 1 attaches probability (S1, S2) = (5,) and Player 2 attaches probability (T1, T2, T3) = (qı. 42, 1 – q1 - 42) where 0 < qi < , and q2 = %3D Player 1 attaches probability (S1, S2) = (,) and player 2 attaches probability (T1, T2, T3) = (1.42, 1- 91-92) where 0 s q1s and q2 =

Managerial Economics: A Problem Solving Approach
5th Edition
ISBN:9781337106665
Author:Luke M. Froeb, Brian T. McCann, Michael R. Ward, Mike Shor
Publisher:Luke M. Froeb, Brian T. McCann, Michael R. Ward, Mike Shor
Chapter16: Bargaining
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8) Find the mixed strategy Nash equilibrium of the following normal form game.
Player 2
T1
T2
T3
2, 3 3, 5 1, 1
Player 1
S2
1, 4 4, 3 0, 5
Player 1 attaches probability (S1, S2) = () and Player 2 attaches probability (T1, T2, T3) = ( )
Player 1 attaches probability (S1, S2) = (.) and Player 2 attaches probability
(T1, T2, T3) = (qi, 42, 1 – q1 – 92) where q1
, and 0 < q2 S
%3D
Player 1 attaches probability (S1, S2) = (G,;) and Player 2 attaches probability
(T1, T2, T1) = (qı.42, 1 – q1 – 42) where 0 < qi <, and q2 =
3.
Player 1 attaches probability (S1, S) = (;, -) and player 2 attaches probability
(T1, T2, T3) = (1.42, 1- q1- 42) where 0 s qı s and q2 =
Transcribed Image Text:8) Find the mixed strategy Nash equilibrium of the following normal form game. Player 2 T1 T2 T3 2, 3 3, 5 1, 1 Player 1 S2 1, 4 4, 3 0, 5 Player 1 attaches probability (S1, S2) = () and Player 2 attaches probability (T1, T2, T3) = ( ) Player 1 attaches probability (S1, S2) = (.) and Player 2 attaches probability (T1, T2, T3) = (qi, 42, 1 – q1 – 92) where q1 , and 0 < q2 S %3D Player 1 attaches probability (S1, S2) = (G,;) and Player 2 attaches probability (T1, T2, T1) = (qı.42, 1 – q1 – 42) where 0 < qi <, and q2 = 3. Player 1 attaches probability (S1, S) = (;, -) and player 2 attaches probability (T1, T2, T3) = (1.42, 1- q1- 42) where 0 s qı s and q2 =
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