8 Co 18 Law of conservation of energy me + c²+ m₂-c²+Ee+ + Ee= = E₁ + E₂ me₁ = me- = 9.11× 10³ kg C=299792458 m/s The kinetic energy of election and Position is 10 times smaller than me+c² or me-c² and can charge: -1.602176634x10¹7 C regarded as 0. 0 prove that detected y-raj energy is 511 kev @ There is distribution in energy of y-ray that is actually detected. Why?
8 Co 18 Law of conservation of energy me + c²+ m₂-c²+Ee+ + Ee= = E₁ + E₂ me₁ = me- = 9.11× 10³ kg C=299792458 m/s The kinetic energy of election and Position is 10 times smaller than me+c² or me-c² and can charge: -1.602176634x10¹7 C regarded as 0. 0 prove that detected y-raj energy is 511 kev @ There is distribution in energy of y-ray that is actually detected. Why?
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Transcribed Image Text:8
Ca
18
Law of conservation of energy
m₂ + c + m₂-c²+Ee+ + Ee= = E₁ + E₂
me₁ = me- = 9-11x10 ³¹1 kg
C=299792458 m/s
The kinetic energy of election and
Position is 10 times smaller than
me+c² or me-c²² and can
charge: -1.602176634x107C
0 prove that detected y-ray energy is 511 kev
@ There is distribution in energy of y-ray
that is actually defected. Why?
regarded as o.
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