(8) A thin lens is made from material having an index of refraction of 1.65. The front surface of the lens has a radius of curvature of +12.0 cm. The back surface of the lens has a radius of curvature of -12.0 cm. (i) What is the focal length of the lens? (ii) Is this a converging or diverging lens? Justify your answer by showing your work. (iii) If an object is placed 18.0 cm in front of this lens, determine the location of the image formed (in cm). (iv) What is the magnification of this lens? (v) Is the image real or virtual? Justify your answer by showing your work.

(b) Explain in detail how images are formed in convex mirrors. In your explanation use diagrams where appropriate and show how both real and virtual images can be formed in a concave mirror.

A diverging lens with focal length f1 = −20 cm is placed 50cm to the left of a converginglens with f2 = 10 cm. If a 5 cm tall object is placed 20 cm to the left of the diverging lens then answerthe following. a) What is position of the final image created by the two lens system with respect to theconverging lens? Draw the ray tracing diagram in the figure above and be sure to include at least twospecial rays for each lens. b) What is the total magnification? c) What is the total height and orientation of the final image? Is the image real or virtual? Why?

The top of a swimming pool is at ground level. If the pool is 5.00m deep (from ground level) and the surface of the pool water is 0.200m below the edge of the pool, how far below ground level does the bottom of the pool appear to be located? ( nwater =1.33 )\