8 00 Vo = Vox i = (30.6 m/s) i until it encounters a smooth inclined hill. It climbs the hill with constant velocity V₁ = V₁₁x + V₁yĴ = (44.2 m/s)i + (3.23 m/s)ĵ as indicated in the figure. The period of time during which the car changes its velocity is At = 3.49 s.

A common graphical representation of motion along a straight line is the v vs. t graph, that is, the graph of (instantaneous) velocity as a function of time. In this graph, time t is plotted on the horizontal axis and velocity v on the vertical axis. Note that by definition, velocity and acceleration are vector quantities. In straight-line motion, however, these vectors have only a single nonzero component in the direction of motion. Thus, in this problem, we will call the velocity and a the acceleration, even though they are really the components of the velocity and acceleration vectors in the direction of motion, respectively. Figure U₁(m/s) 2.0 1.5 1.0 0.5 1(s) 0 10 20 30 40 50 1 of 1 (Figure 1) is a plot of velocity versus time for a particle that travels along a straight line with a varying velocity. Refer to this plot to answer the following questions. Part A What is the initial velocity of the particle, vo? Express your answer in meters per second. ▸ View Available Hint(s) V₁ =…

A vehicle travels at a speed of 4 m/ sec along a horizontal Circular road that has a radius of 50m its speed is then increased by ú= (0.05.s) m/sec² for a short distance from S = 0, where s is in meters. Calculate the magnitude of its acceleration when it has moved s = 10m in ml sec².

A runner, jogging along a straight-line path, starts at a position 60.0 m east of a milestone marker and heads west. After a short time interval he is 15.7 m west of the mile marker. Choose east to be the positive x-direction. What is the runner’s displacement from his starting point? Enter a positive value if the displacement is toward east of the milestone and a negative value if the displacement is toward west of the milestone.