77. For the reaction SbCls(g) AG (SbCls)=-334.34 kJ/mol SbCl3(g) + Cl2(g), AG°f (SbC13)=-301.25 kJ/mol AH (SbCls)=-394.34 kJ/mol AH°(SbC13)=-313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure. A. 1.31 x 103 B. 1.11 x 103 C. 1.91 x 102 D. 1.71 x 102 E. None of the above

Use the References to access important values if needed for this question. -87.9 kJ, and Kc Consider the following system at equilibrium where AH 500 K: = The value of Qc Ois greater than K O is equal to Ke O is less than Ke = PC13 (g) + Cl₂ (g) ⇒ PC15 (9) When 0.36 moles of PC15 (9) are added to the equilibrium system at constant temperature: The value of Kc Oincreases decreases O remains the same The reaction must Orun in the forward direction to reestablish equilibrium run in the reverse direction to reestablish equilibrium O remain in the current position, since it is already at equilibrium The concentration of PC13 will O increase decrease O remain the same 83.3, at Previou

For a particular reaction at 140.6 °C, AG = 560.53 kJ/mol, and AS = 131.79 J/(mol · K). Calculate AG for this reaction at -68.1 °C. AG = 467.18 kJ/mol Incorrect

For a particular reaction at 179.4 °C, AG = -801.20 kJ, and AS = 915.51 J/K. Calculate AG for this reaction at -52.5 °C. AG =